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2 years ago

10

The tighter the probability distribution of its expected future returns, the greater the risk of a given investment as measured

by its standard deviation.
a. Trueb. False

1 answer:

shusha [124]2 years ago

5 0

Answer:

The answer is false

Step-by-step explanation:

the greater the risk of given investment measured by its standard deviation is false.

You might be interested in

Which measure is the largest? 1.2 km, 120,600 cm, 1,220,000 mm, 120 meters

aalyn [17]

The answer would be 1,220,000mm.

You can do this if you convert all the measures into one unit. Let us convert all into km.

The first one is already in km, so we do not need to covert it.

Let's start with converting 1,220,000mm to km.

There are 1, 000,000 mm in one km.

$1,220,000X \frac{1km}{1,000,000mm} = 1.22km$

So there are 1.22km in 1,220,000mm.

Next, we have 120m. There are 1,000m in 1km.

$120mX \frac{1km}{1,000} =0.12km$

There are 0.12km in 120m

Now you can see that 1,220,000mm is the longest.

4 0

1 year ago

The number of bacteria in a culture is given by the function n(t) =950e^0.45t Where t is measured in hours A) what is the contin

tatiyna

Answer:

a) The continuous rate of growth of this bacterium population is 45%

b) Initial population of culture at t = 0 is 950 bacteria

c) number of bacterial culture contain at t = 5 is 9013 bacteria

Step-by-step explanation:

The number of bacteria in a culture is given by

n(t) = 950 $e^{0.45t}$

a) rate of growth is

Bacteria growth model N(t) = no $e^{rt}$

Where r is the growth rate

hence r = 0.45

= 45%

b) Initial population of culture at t = 0

n(0) = 950 $e^{0.45(0)}$

= 950 $e^{0}$

= 950 bacteria

c) number of bacterial culture contain at t = 5

n(5) = 950 $e^{0.45(5)}$

= 950 $e^{2.25}$

= 9013.35

= 9013 bacteria

6 0

2 years ago

Yesterday, two friends went into a bank to open savings accounts. Allie started by putting $783 in her account, and she will dep

posledela

<u>Answer:</u>

Both accounts of Nick and Allie will have same amount of $864 in time period of 4 weeks.

<u>Solution: </u>

Given, Yesterday two friends went into a bank to open savings accounts.

Allie started by putting $783 in her account, and she will deposit an additional $27 each week.

Nick made no initial deposit, but he will add $288 more each week.

In a few weeks, the friends will have the same account balance.

Here, account balance of Allie for every week forms an A.P as

783, 810, 837, ……. With common difference 27

And, account balance of nick for every week will be

0, 288, 576, …….. with common difference 288

Let, after n weeks the balance in both accounts be equal.

Then, nth term of both series will be equal, we know that, nth term tn of A.P is a + (n – 1)d

Where, a is first term, d is common difference and n is number of terms.

Now, nth term of allie series = nth term of nick series.

783 + (n – 1) x 27 = 0 + (n – 1) x 288

Here, we used same n for both sides because n represents number of weeks and it is common to both

783 + 27n – 27 = 288n – 288

756 + 288 = 288n – 27n

261n = 1044

n = 4.

So, it will take 4 weeks to have same balance and now, substitute n value in nth term of nick series.

$4 \text { th term }=0+(4-1) \times 288 \rightarrow 4^{\text {th }} \text { term }=3 \times 288=864$

Hence, both accounts will have same amount of $864 in time period of 4 weeks

4 0

2 years ago

plz help whats the answer to this question !!! calculate the mass of a gold bar that is 18.00cm long, 9.21cm wide, and 4.45cm hi

erik [133]

We have to find the mass of the gold bar.

We have gold bar in the shape of a rectangular prism.

The length, width, and the height of the gold bar is 18.00 centimeters, 9.21 centimeters, and 4.45 centimeters respectively.

First of all we will find the volume of the gold bar which is given by the volume of rectangular prism:

Volume of the gold bar $= length \times width\times height$

Plugging the values in the equation we get,

Volume of the gold bar $=18.00 \times 9.21 \times 4.45= 737.721cm^3$

Now that we have the volume we can find the mass by using the formula,

$Mass= density \times volume$

The density of the gold is 19.32 grams per cubic centimeter. Plugging in the values of density and volume we get:

$Mass = 19.32\times 737.721=14252.769$ grams

So, the mass of the gold bar is 14252.769 grams

7 0

2 years ago

The first terms of an infinite geometric sequence, Un are 2, 6, 18, 54... The first terms of a second infinite geometric sequenc

gladu [14]

Answer:

r = 9 and m = 112

Step-by-step explanation:

$\sum_{k=1}^{225}W_{k}=\sum_{k=0}^{m}4r^{k}$

Write W in terms of U and V.

$\sum_{k=1}^{225}(U_{k}+V_{k})=\sum_{k=0}^{m}4r^{k}\\\sum_{k=1}^{225}U_{k}+\sum_{k=1}^{225}V_{k}=\sum_{k=0}^{m}4r^{k}$

Define U and V using geometric series formula.

$\sum_{k=1}^{225}2(3)^{k-1}+\sum_{k=1}^{225}2(-3)^{k-1}=\sum_{k=0}^{m}4r^{k}$

Use sum of geometric series formula.

$2(\frac{1-(3)^{225}}{1-3})+2(\frac{1-(-3)^{225}}{1-(-3)})=4(\frac{1-(r)^{m+1}}{1-r})$

Simplify.

$-1(1-3^{225})+\frac{1+3^{225}}{2}=4(\frac{1-(r)^{m+1}}{1-r})\\-1+3^{225}+\frac{1}{2}+\frac{3^{225}}{2}=4(\frac{1-(r)^{m+1}}{1-r})\\-\frac{1}{2}+\frac{3(3^{225})}{2}=4(\frac{1-(r)^{m+1}}{1-r})\\\frac{-1+3(3^{225})}{2}=4(\frac{1-(r)^{m+1}}{1-r})\\\frac{-1+3^{226}}{2}=4(\frac{1-(r)^{m+1}}{1-r})\\4\frac{-1+3^{226}}{8}=4(\frac{1-(r)^{m+1}}{1-r})\\4\frac{1-3^{226}}{-8}=4(\frac{1-(r)^{m+1}}{1-r})\\4\frac{1-9^{113}}{1-9}=4(\frac{1-(r)^{m+1}}{1-r})$

Therefore, r = 9 and m = 112.

8 0

1 year ago