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VLD [36.1K]
2 years ago
8

Triangle cde maps to triangle lmn with the transformation (x,y) —> (x+3,y-2) —> (2/3x, 2/3y)

Mathematics
1 answer:
Mamont248 [21]2 years ago
4 0
The answer is 890 best answer
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Determine which equations below, when combined with the equation 3x-4y=2, will form a system with no solutions. Choose all that
svetoff [14.1K]
Two equations will not have solution if they are parallel and have different y-intercepts. Parallel lines have the same slope. In a slope-intercept form, the equation of the line can be expressed as,       
 
        y = mx + b 

where m is slope and b is the y-intercept.

Given: 3x - 4y = 2
Slope-intercept: y = 3x/4 - 1/2

A. 2y = 1.5x - 2
Slope-intercept: y = 3x/4 - 1

B. 2y = 1.5x - 1
Slope-intercept:  y = 3x/4 - 1/2

C. 3x + 4y = 2
Slope-intercept:  y = -3x/4 + 1/2

D. -4y + 3x = -2
Slope-intercept: y = 3x/4 + 1/2

Hence, the answers to this item are A and D. 
6 0
2 years ago
Let L be the line with parametric equations x=2+t, y=1-t, z=1+3t.Let v=(1,2,0).Find vectors w1 and w2 such that v= w1 + w2, and
charle [14.2K]

Answer:

w1 = (-1/11, 1/11, -3/11)

w2 = (12/11, 21/11, 3/11)

Step-by-step explanation:

Direction ratio of w1 = Direction ratio of L (because parallel) = K+(1, -1, 3)

Let <a,b,c> be direction ratio of w2.

Then, <a,b,c>. <1,-1,3> = 0

a-b+3c = 0

v = w1 + w2

(1, 2, 0) = k(1, -1, 3) + (a, b, c)

a + k = 1

b - K = 2

c - 3k = 0

Solving 4 equations, a = 12/11, b= 21/11, c = 3/11, k=-1/11

So, w1 = -1/11(1, -1 ,3) = (-1/11, 1/11, -3/11)

w2 = (12/11, 21/11, 3/11)

6 0
2 years ago
Solve the following multiplication and division problems. a. 8 T. 1,398 lb. 14 oz. × 6 b. 349 lb. 6 oz. ÷ 130 c. 6 T. 294 lb. ÷
tester [92]

Answer:  a) 278382 oz

b) 43 oz

c) 64.1 oz

Step-by-step explanation:

a) 8 T. 1,398 lb. 14 oz. × 6

First we need to change it in 'oz'.

As we know that

1\ ton=32000\ oz\\\\1\ lb=16\ oz

so, it becomes,

8\times 32000+1398\times 16+14\ oz\\\\=278382\ oz

8 T. 1,398 lb. 14 oz. × 6 becomes

278382\times 6\\\\=1670292\ oz

b) 349 lb. 6 oz. ÷ 130

It becomes,

349\times 16+6\ oz\\\\=5590\ oz\\\\\text{ at last it becomes}\\\\=\frac{5590}{130}\\\\=43\ oz

c) 6 T. 294 lb. ÷ 3,071

First it becomes,

6\times 32000+294\times 16\ oz\\\\=196704\ oz

At last it becomes,

\frac{196704}{3071}\\\\=64.1\ oz

Hence, a) 278382 oz

b) 43 oz

c) 64.1 oz

6 0
2 years ago
Read 2 more answers
a box contains 2 purple marbles, 9 orange marble and seven yellow marble. if you pick 2 without looking wha is the probability t
Ulleksa [173]

Angood job

swer:

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
In a game of cornhole, Sasha tossed a bean bag and it landed at the edge of the hole. The hole can be represented by the equatio
Nitella [24]

In the game of cornhole, when Sasha tossed a bean bag to the edge of the hole, in which the equations of the hole and bean bag's path are x² + y² = 5 and y = 0.5x² + 1.5x - 4, respectively, she could have tossed her bean bag to the points (1, -2) or (2, 1).              

 

To find the points in which she could have tossed her bean bag, we need to intersect the two equations of the function as follows.

<u>The equation for the hole</u>

x^{2} + y^{2} = 5   (1)

<u>The equation for the path of the bean bag</u>

y = 0.5x^{2} + 1.5x - 4    (2)

By entering equation (2) into (1) we have:  

x^{2} + (0.5x^{2} + 1.5x - 4)^{2} = 5

x^{2} + 0.25x^{4} + 1.5x^{3} - 4x^{2} + 2.25x^{2} - 12x + 16 = 5    

0.25x^{4} + 1.5x^{3} - 0.75x^{2} - 12x + 11 = 0

By solving for <em>x</em>, we have:

x₁ = 1

x₂ = 2

Now, for <em>y</em> we have (eq 2):

  • <u>x₁ = 1</u>    

y_{1} = 0.5(1)^{2} + 1.5(1) - 4 = -2

  • <u>x₂ = 2</u>

y_{2} = 0.5(2)^{2} + 1.5(2) - 4 = 1                                              

Therefore, the points are (1, -2) or (2, 1).

To find more about intersections, go here: brainly.com/question/4977725?referrer=searchResults        

I hope it helps you!

8 0
2 years ago
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