2.50x = Ethan’s total sold -6 (15/2.50=6)
2x = Chloe’s total sold
2.50(12) = 30 - 6 = 24
2(12) = 24
They both sold 12 candy bars
Answer: 0.31
Step-by-step explanation:
Let A denotes the event of Tampa Bay Buccaneers will score a touchdown on their opening drive and B denote the event that their defense will have 3 or more sacks in the game.
Given : P(A)=0.14 P(B) = 0.31 P(A or B)=0.14
Formula : P(A and B)= P(A) + P(B) - P(A or B)
Now, the probability that they will both score a touchdown on the opening drive and have 3 or more sacks in the game will be :-
P(A and B)= 0.14 + 0.31 - 0.14=0.31
Hence, the required probability : 0.31
we know that
The measurement of <u>the external angle</u> is the semi-difference of the arcs it includes.
In this problem
![21\°=\frac{1}{2}[arc\ RU-arc\ SU]](https://tex.z-dn.net/?f=21%5C%C2%B0%3D%5Cfrac%7B1%7D%7B2%7D%5Barc%5C%20RU-arc%5C%20SU%5D)
Solve for the measure of arc SU
![42\°=[arc\ RU-arc\ SU]](https://tex.z-dn.net/?f=42%5C%C2%B0%3D%5Barc%5C%20RU-arc%5C%20SU%5D)


therefore
the answer is
The measure of the arc SU is 
Since the sum of all probabilities of all all elementary events will always be equal to 1. Furthermore, the probabilities of all mutually exclusive set of events that is part of the entire sample space will always be total of 1.
So in the problem, the answer is 1/8.
1/8 for red + 3/8 for green + 3/8 for yellow + 1/8 for blue = 8/8 or 1.
Answer:
tan−1(StartFraction 6.9 Over 9.8 EndFraction)
Step-by-step explanation:
tan−1(StartFraction 6.9 Over 9.8 EndFraction)
tan = opp/adj = 9.8/6.9
tan -1 = 1 / tan = 1 / (9.8 /6.9) = 6.9 /9.8