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kobusy [5.1K]
2 years ago
7

Hailey has a rectangular bedspread that measures 890 cm by 2891 cm. She wants to sew a fringe around the edge of the bedspread.

What length of fringe does hailey need to buy
Mathematics
2 answers:
OverLord2011 [107]2 years ago
4 0

Answer:

7562\text{ cm}=75.62 \text{ m}

Step-by-step explanation:

We have been given that Hailey has a rectangular bedspread that measures 890 cm by 2891 cm. She wants to sew a fringe around the edge of the bedspread. We are asked to find the length of the fringe.

The length of the fringe that Hailey needs will be equal to perimeter of the rectangle. We know that perimeter of the rectangle is two times the sum of length and width.

\text{Length of required fringe}=2(890\text{ cm}+2891\text{ cm})

\text{Length of required fringe}=2(3781\text{ cm})

\text{Length of required fringe}=7562\text{ cm}

We can convert 7562 cm into meters by dividing by 100 as 1 meter equals 100 cm.

7562\text{ cm}=\frac{7561}{100}\text{ m}=75.62 \text{ m}

7562\text{ cm}=75.62 \text{ m}

Therefore, Hailey needs 7562 cm or 75.62 meters of fringe.

gavmur [86]2 years ago
3 0

Answer:

Haley requires 7562 cm of fringe to sew around the edge of the bedspread.

Step-by-step explanation:

We are given the following in the question:

Dimension of rectangular bedspread:

Width, w = 890 cm

Length, l = 2891 cm

We have to calculate the length of fringe required to sew around the edge of the bedspread.

Length of fringe = Perimeter of rectangular bedspread

P = 2(l+w)\\P = 2(2891+890)\\P=7562\text{ cm}

Thus, Haley requires 7562 cm of fringe to sew around the edge of the bedspread.

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Answer:

The constant term in the function is 5

Step-by-step explanation:

we have

f(x)=x^{2}+8x+b

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The x-intercept is the value of x when the value of the function is equal to zero

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substitute any of the intercepts in the function

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0=(-3)^{2}+8(-3)+b

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2 years ago
Shannon rolls 2 fair dice and adds the results from each. Work out the probability of getting a total of 13.
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0.

Step-by-step explanation:

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Since each die has 6 sides, the most you can get from the two dice are 6 + 6 = 12. Therefore, getting a 13 is impossible. So, there is a probability of 0.

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2 years ago
Chandra created a budget matrix based on her regular and expected expenses for the year. Expense Jan. Feb. Mar. Apr. May June Ju
Ivan

Answer:

Chandra's Average Monthly Expenses are;

1) For Both Jan and Feb are $269

2) For the remaining 10 months each are $244

Step-by-step explanation:

From Chandra's matrix all monthly expenses are all same that is,

Cell phone $71, Rent $1,025, Gym $75, Internet $25, Auto insurance $425, Gas $ 120, Food $145. which are all the expenses carried out every month for 12 months.

That means Chandra carries out a total of 7 expenses for the month of January and February while she carried a total of 6 expenses for the remaining 10 month which was noted from the matrix that Auto insurance was carried out only in the month of January and February.

Therefore, you start by adding up each month total expenses, which are ;

January = $71 + $1,025 + $75 + $25 + $425 + $120 + $145 = $1886

February = $71 + $1,025 + $75 + $25 + $425 + $120 + $145 = $1886

March = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

April = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

May = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

June = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

July= $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

August = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

September = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

October = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

November = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

December = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

Therefore Chandra's Average Monthly Expenses are:

1) January & February  = \frac{71 + 1,025 + 75 + 25 + 425 + 120 + 145}{7} = \frac{1886}{7} = 269.4286 to the nearest cent

≅ $269

2) For the remaining 10 month are = \frac{71 + 1,025 + 75 + 25  + 120 + 145}{6} = \frac{1461}{6}= 243.5 to the nearest cent

≅ $244

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