answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
sveticcg [70]
1 year ago
12

Gwen buys 3 identical pairs of shoes at Store a. She pays $110.25 after the discount. what is the original price of each pair?

Mathematics
2 answers:
emmasim [6.3K]1 year ago
5 0
In perspective this looks tricky but really its no ;) just follow it slowly.
110.25  is your total cost 
3 is how many you bought.
So doing division 3/110.25= 36.75
CHECK: 36.75 + 36.75 + 36.75 = 110.25.
Hope this helps.
Rom4ik [11]1 year ago
5 0

Answer:

Gwen buys 3 identical pairs of shoes at Store.

She pays $110.25 after the discount.

So, cost of each pair will be = \frac{110.25}{3}= 36.75 dollars

As the discount is not given, but if it was given, you can find the original price by adding this cost of each pair with discount price.

You might be interested in
The perimeter of a square is 80-64y units. Which expression can be used to show the side length of one side of the square?
nalin [4]
I think it’s 20-16y :)
8 0
2 years ago
Read 2 more answers
Solve the recurrence relation: hn = 5hn−1 − 6hn−2 − 4hn−3 + 8hn−4 with initial values h0 = 0, h1 = 1, h2 = 1, and h3 = 2 using (
musickatia [10]
(a) Suppose h_n=r^n is a solution for this recurrence, with r\neq0. Then

r^n=5r^{n-1}-6r^{n-2}-4r^{n-3}+8r^{n-4}
\implies1=\dfrac5r-\dfrac6{r^2}-\dfrac4{r^3}+\dfrac8{r^4}
\implies r^4-5r^3+6r^2+4r-8=0
\implies (r-2)^3(r+1)=0\implies r=2,r=-1

So we expect a general solution of the form

h_n=c_1(-1)^n+(c_2+c_3n+c_4n^2)2^n

With h_0=0,h_1=1,h_2=1,h_3=2, we get four equations in four unknowns:

\begin{cases}c_1+c_2=0\\-c_1+2c_2+2c_3+2c_4=1\\c_1+4c_2+8c_3+16c_4=1\\-c_1+8c_2+24c_3+72c_4=2\end{cases}\implies c_1=-\dfrac8{27},c_2=\dfrac8{27},c_3=\dfrac7{72},c_4=-\dfrac1{24}

So the particular solution to the recurrence is

h_n=-\dfrac8{27}(-1)^n+\left(\dfrac8{27}+\dfrac{7n}{72}-\dfrac{n^2}{24}\right)2^n

(b) Let G(x)=\displaystyle\sum_{n\ge0}h_nx^n be the generating function for h_n. Multiply both sides of the recurrence by x^n and sum over all n\ge4.

\displaystyle\sum_{n\ge4}h_nx^n=5\sum_{n\ge4}h_{n-1}x^n-6\sum_{n\ge4}h_{n-2}x^n-4\sum_{n\ge4}h_{n-3}x^n+8\sum_{n\ge4}h_{n-4}x^n
\displaystyle\sum_{n\ge4}h_nx^n=5x\sum_{n\ge3}h_nx^n-6x^2\sum_{n\ge2}h_nx^n-4x^3\sum_{n\ge1}h_nx^n+8x^4\sum_{n\ge0}h_nx^n
G(x)-h_0-h_1x-h_2x^2-h_3x^3=5x(G(x)-h_0-h_1x-h_2x^2)-6x^2(G(x)-h_0-h_1x)-4x^3(G(x)-h_0)+8x^4G(x)
G(x)-x-x^2-2x^3=5x(G(x)-x-x^2)-6x^2(G(x)-x)-4x^3G(x)+8x^4G(x)
(1-5x+6x^2+4x^3-8x^4)G(x)=x-4x^2+3x^3
G(x)=\dfrac{x-4x^2+3x^3}{1-5x+6x^2+4x^3-8x^4}
G(x)=\dfrac{17}{108}\dfrac1{1-2x}+\dfrac29\dfrac1{(1-2x)^2}-\dfrac1{12}\dfrac1{(1-2x)^3}-\dfrac8{27}\dfrac1{1+x}

From here you would write each term as a power series (easy enough, since they're all geometric or derived from a geometric series), combine the series into one, and the solution to the recurrence will be the coefficient of x^n, ideally matching the solution found in part (a).
3 0
2 years ago
Liam is swimming at 3 kilometers per hour. How long will it take Liam to travel 4.5 kilometers?
kkurt [141]
Answer:

One hour and thirty minutes.

Explanation:

3km = 1 hour

1.5km = 30 min (half of distance, half of time)

4.5km = 1 hour and 30 min
5 0
2 years ago
Read 2 more answers
The angle measures associated with which set of ordered pairs share the same reference angle
Trava [24]

Answer:

Option 3 is right.

Step-by-step explanation:

Reference angle of x is obtained by either 180-x, 180+x. or 360-x depending on the posiiton of terminal whether II quadrant or iv quadrant, or iii quadrant, etc.

In whatever way we find reference angles,

cos will remain cos only and sin will remain sin only there may be only changes in sign.

Of all the ordered pairs given, we find that I, II, and Iv there is a switch over form cos to sine and sin to cos.  Hence these options cannot be for reference angles.

III option is (-\frac{1}{2} ,\frac{-\sqrt{3} }{2} )(\frac{1}{2} ,\frac{\sqrt{3} }{2} )

show that both sign and cos changed sign.  This is possible only in III quadrant.

ie reference angle of orignal angle t = 180+t

SO this option is right.

7 0
1 year ago
Read 2 more answers
Round 2.1349 to the nearest hundredth. Explain in your own words why you round the number the way you do. Use a number line to s
zhenek [66]

Answer:

2.13

Step-by-step explanation:

because 2.1349 is closer to 2.13 than 2.14 because the number 4 is less than 5 so it's closer to 0

3 0
2 years ago
Read 2 more answers
Other questions:
  • Subtract measurement with Same Difference Theorem
    6·3 answers
  • Suppose that a class contains 15 boys and 30 girls, and that 10 students are to be selected at random for a special assignment.
    5·1 answer
  • Which transformation maps hexagon 1 into 3?
    15·1 answer
  • A scuba diving instructor takes a group of students to the depth of 54.96 feet. Then they ascend 22.38 feet to see some fish. Wh
    8·2 answers
  • The table shows the number of championships won by the baseball and softball leagues of three youth baseball divisions organized
    7·1 answer
  • Company A charges $331.35 per week for a compact car with unlimited miles. Company B charges $175 per week plus $0.53 per mile,
    8·1 answer
  • An airline gathers data on late departures and early arrivals over a month. It finds that the probability of a late departure is
    5·2 answers
  • Data show that men between the ages of 20 and 29 in a general population have a mean height of 69.3​ inches, with a standard dev
    7·1 answer
  • Giovanna has two possible driving routes to her new workplace, and she is having a hard time figuring out which is faster. The f
    8·1 answer
  • Directions: Complete a graphic organizer of twelve verbs which may either be regular or irregular.
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!