Given:
Original price = 20
reduces selling price by 25% every month it's not sold.
First markdown month:
20 * (100%-25%) = 20 * 75% = 15
Second markdown month
15 * 75% = 11.25
Macy, employee gets a 50% discount off the current price.
11.25 * 50% = 5.625
11.25 - 5.625 = 5.625 or 5.63
The pre-tax price of the shirt for Macy will be $5.63
Answer: The required system of equations are
y = 30x
13x + y = 258
Step-by-step explanation:
Let x represent the number of hours
that the driver worked.
Let y represent the number of miles that the truck drove.
For every truck that goes out, Mason must pay the driver $13 per hour of driving and also has an expense of $1 per mile driven for gas and maintenance. If on a particular day, his total expenses for the driver, gas and truck maintenance were $258, it means that
13x + y = 258
On that particular day, the driver drove an average of 30 miles per hour.
Speed = distance/time
It means that
y/x = 30
y = 30x
Answer: C. 70 percent
Step-by-step explanation:
Given, Time for the first unit = 50 minutes
Time for the second unit = 35 minutes
The unit improvement factor learning curve = (The time for the second unit) ÷ (time for the first unit) x 100.
So, The unit improvement factor learning curve = 35÷ 50 × 100 = 70 percent.
Hence, the correct option is "C. 70 percent".
Answer:
<h3>AC=96 units.</h3>
Step-by-step explanation:
We are given a parallelogram ABCD with diagonals AC and BD intersect at point E.
, and CE=6x .
<em>Note: The diagonals of a parallelogram intersects at mid-point.</em>
Therefore, AE = EC.
Plugging expressions for AE and EC, we get
Subtracting 6x from both sides, we get
Factoriong quadratic by product sum rule.
We need to find the factors of -16 that add upto -6.
-16 has factors -8 and +2 that add upto -6.
Therefore, factor of quadratic is (x-8)(x+2)=0
Setting each factor equal to 0 and solve for x.
x-8=0 => x=8
x+2=0 => x=-2.
We can't take x=-2 as it's a negative number.
Therefore, plugging x=8 in EC =6x, we get
EC = 6(8) = 48.
<h3>AC = AE + EC = 48+48 =96 units.</h3>
Answer:
Option C. The time in seconds that passed before the printer started printing pages
see the explanation
Step-by-step explanation:
Let
y ---->the number of pages printed.
x ---> the time (in seconds) since she sent a print job to the printer
we know that
The x-intercept is the value of x when the value of y is equal to zero
In the context of the problem
The x-intercept is the time in seconds that passed before the printer started printing pages (the number of pages printed is equal to zero)
