The tread life of tires mounted on light-duty trucks follows the normal probability distribution with a population mean of 60,00
0 miles and a population standard deviation of 4,000 miles. Suppose you bought a set of four tires; what is the likelihood the mean tire life of these four tires is more than 66,000 miles?
1 answer:
Answer:
0.0013
Step-by-step explanation:
To do this, we need to use a normal distribution table with Z score values, like the one I'm attaching here.
Now, the expression to calculate the Z value is the following:
Z = x - μ / (σ/√n)
Where:
μ: mean
σ: standard deviation
x: value required
n: sample population
Now that we have the data, let's calculate the Z value:
Z = 66,000 - 60,000 / (4000/√4)
Z = 3
Now, let's look at the table to get the value that belongs to this Z score. According to the table, it's 0.0013
Therefore, the likelihood would be 0.0013
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