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Ierofanga [76]
2 years ago
10

Karina solves the system using linear combination and arrives at the equation 116y = 96.28. She then solves this equation for y.

Which statement explains Karina’s solution
Mathematics
1 answer:
igomit [66]2 years ago
5 0
116y =96.28
116y = 96.28
----      ---------
116        116

y = .83
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Nathan had an infection, and his doctor wanted him to take penicillin. Because Nathan’s father and paternal grandfather were all
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There is a 73.5% chance that Nathan is allergic to penicillin and the test predicts it.

75% * 98% = 73.5%

.75 * .98 = .735
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2 years ago
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Rahm used a payment plan to purchase wood for a home project. The wood he bought cost $500. The clerk at the store offered him t
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2 years ago
A car was purchased for $25,000. Research shows that the car has an average yearly depreciation rate of 18.5%. Create a function
vitfil [10]

Answer:

V(t) = 25000 * (0.815)^t

The depreciation from year 3 to year 4 was $2503.71

Step-by-step explanation:

We can model V(t) as an exponencial function:

V(t) = Vo * (1+r)^t

Where Vo is the inicial value of the car, r is the depreciation rate and t is the amount of years.

We have that Vo = 25000, r = -18.5% = -0.185, so:

V(t) = 25000 * (1-0.185)^t

V(t) = 25000 * (0.815)^t

In year 3, we have:

V(3) = 25000 * (0.815)^3 = 13533.58

In year 4, we have:

V(4) = 25000 * (0.815)^4 = 11029.87

The depreciation from year 3 to year 4 was:

V(3) - V(4) = 13533.58 - 11029.87 = $2503.71

7 0
2 years ago
The fish population of Lake Collins is decreasing at a rate of 3% per year. In 2004 there were about 1,300 fish. Write an expone
Sergeu [11.5K]
For this case we have a function of the form:
 y = A * (b) ^ x
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 y = 1300 * (0.97) ^ x

 For 2010 we have:
 y = 1300 * (0.97) ^ 6

y = 1083
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y = 1300 * (0.97) ^ x
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6 0
2 years ago
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A local trucking company fitted a regression to relate the travel time (days) of its shipments as a function of the distance tra
alina1380 [7]

Answer:

1.734

Step-by-step explanation:

Given that:

A local trucking company fitted a regression to relate the travel time (days) of its shipments as a function of the distance traveled (miles).

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And an Estimated standard error of the slope = 0.0053

the critical value for a right-tailed test to see if the slope is positive, using ∝ = 0.05 can be computed as follows:

Let's determine the degree of freedom df = n - 1

the degree of freedom df = 20 - 2

the degree of freedom df =  18

At the level of significance ∝ = 0.05 and degree of freedom df =  18

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t_{0.05, 18} = 1.734

5 0
2 years ago
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