Question

The owner of a manufacturing plant employs eighty people. As part of their personnel file, she asked each one to record to the nearest one-tenth of a mile the distance they travel one way from home to work. The distances for a random sample of six employees are listed below:
26 32 29 16 45 19

Required:
Compute mean, variance, and standard deviation for these data, with a step-by-step explanation for each. Round your answer to one more decimal place than the original data.

Answer 1

Answer:

Mean of the sample = 27.83

The variance of the the sample = 106.96

Standard deviation of the sample = 10.34

Step-by-step explanation:

Step(i):-

Given random sample of six employees

x     26    32    29    16     45    19

mean of the sample

$x^{-} = \frac{26+32+29+16+45+19}{6} = 27.83$

Mean of the given data = 27.83

Step(ii):-

Given data

x           :       26         32           29           16           45        19

x - x⁻     :      -1.83      4.17        1.17       -11.83     17.17    -8.83

(x - x⁻)²  :    3.3489   17.3889   1.3689   139.9489  294.80 77.9689

∑ (x-x⁻)²  =   534.8245

Given sample size 'n' =6

The variance of given data

           S²  = ∑(x-x⁻)² / n-1  

           $S^{2} = \frac{534.8245}{6-1} = 106.9649$

The variance of the given sample = 106.9649

Step(iii):-

Standard deviation of the given data

$S = \sqrt{variance} = \sqrt{106.9649} =10.3423$

Standard deviation of the sample = 10.3423