What is the correct answer for the calculation of a volume (in ml) with measured numbers 28.58/16 x 8.02 ?

4 and 5 are complements, and 1 and 5 are complements. By the congruent complements theorem, which angle is congruent to 4? 1 2 3

Zepler [3.9K]

The theorem tells you angles complementary to the same angle are congruent. Both 4 and 1 are complementary to 5, so 4 and 1 are congruent.

The angle congruent to 4 is 1.

8 0

2 years ago

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Steve is trying to increase his average pace per mile by running hills. The hill on 1st Avenue rises 3 vertical feet for each ho

marissa [1.9K]

1st Avenue would be more difficult because it’s rise and run is for every one foot forward it is 3 feet up. Meanwhile avenue 16th would start at (3,1) and the rise and run would be for every 3 feet it would go up 1 foot.

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2 years ago

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A study of immunizations among school‑age children in California found that some areas had rates of unvaccinated school‑age chil

Rom4ik [11]

Answer:

Probability that none of the 20 children in such a classroom would be unvaccinated is 0.055.

Step-by-step explanation:

We are given that a classroom of 20 children in one such area where 13.5% of children are unvaccinated.

If there are no siblings in the classroom, we are willing to consider the vaccination status of the 2020 unrelated children to be independent.

The above situation can be represented through binomial distribution;

$P(X=r) = \binom{n}{r} \times p^{r} \times (1-p)^{n-r} ; x = 0,1,2,3,......$

where, n = number of trials (samples) taken = 20 children

r = number of success = none of the 20 children

p = probability of success which in our case is probability that

children are unvaccinated, i.e; p = 13.5%

Let X = Number of children that are unvaccinated

So, X ~ Binom(n = 20, p = 0.135)

Now, Probability that none of the 20 children in such a classroom would be unvaccinated is given by = P(X = 0)

P(X = 0) = $\binom{20}{0} \times 0.135^{0} \times (1-0.135)^{20-0}$

= $1\times 1 \times 0.865^{20}$

= 0.055

Hence, the probability that none of the 20 children in such a classroom would be unvaccinated is 0.055.

8 0

2 years ago

In the rectangular prism below, the length of MR is 8 inches, the length of RS is 9 inches, and the length of ST is 12 inches.

Sever21 [200]

Unfortunately, there's no diagram here! But the prism is described as "rectangular." Thus, the volume is simply (length)(width)(height) cubic inches. Multiply: (8 inches)(9 inches)(12 inches).

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2 years ago

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The weight of people in a small town in missouri is known to be normally distributed with a mean of 154 pounds and a standard de

ad-work [718]

If a random sample of 20 persons weighed 3,460, the sample mean x-bar would be 3460/20 = 173 pounds.
The z-score for 173 pounds is given by:
$z=\frac{173-154}{29}=0.655$
Referring to a standard normal distribution table, and using z = 0.66, we find:
$P(\bar x\ \textless \ 173)=0.7454$
Therefore
$P(\bar x\ \textgreater \ 173)=1-0.7454=0.2546$
The answer is: 0.2546

4 0

2 years ago