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1 year ago

If 300% of 0.18 is equivalent to 20% of b, then b is equivalent to what number?

Mathematics

2 answers:

mote1985 [20]1 year ago

5 0

Answer:

b= 27 5 (0.54) regardless makes 2.7 x 100 =27 where 300% of 0.18 =0.54

Step-by-step explanation:

We need a number that is 20% of b and equal to 5.4

To find 0.54 (= 20% )we can use fractions for percentages 20%= 1/5 or 2.70 thereafter as we do not work in decimals if no fraction in mentioned we get b= 26 and 20% of this is 5.2. Then plug in as above where the answer is 5 (0.54) regardless makes 2.7 x 100 =27 where 300% of 0.18 =0.54 but plug in fractions instead.

tatiyna1 year ago

3 0

Answer:

2.7

Step-by-step explanation:

3*0.18=0.54

0.54/0.2=2.7

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A consumer is considering two different purchasing options for the car of their choice. The first option, which is leasing, is d

AVprozaik [17]

Answer:

y=250x+4000
y=400x+400

Step-by-step explanation:

Given that:

x represents the number of months of ownership; and
y represents the total paid for the car after ‘x' months.

First Option (Leasing)

250x - y + 4000 = 0

Expressing the equation in the Slope-Intercept Form y=mx+b, we have:

y=250x+4000

Second Option (Financing)

$400 for 0 months of ownership, (0,400), and $4400 for 10 months of ownership, (10, 4400).

First, we determine the slope of the line joining (0,400) and (10,4400)

$Slope, m= \dfrac{4400-400}{10-0}= \dfrac{4000}{10}=400$

We have:

y=400x+b

When y=400, x=0

400=400(0)+b

b=400

Therefore, the Slope-Intercept Form of the second option is:

y=400x+400

Significance

In the first option, there is a down payment of $4000 and a monthly payment of $250.
In the second option, there is a down payment of $400 and a monthly payment of $400.

Part B

We notice from the graph that after 24 months, the cost for leasing and financing becomes the same ($10,000). Therefore, a consumer will be better off financing since the downpayment for leasing is higher.

i.e

When x=0, y=$4000 for leasing
When x=0, y=$400 for financing

4 0

2 years ago

And remember the little $4308 pizza-mistake? How many weeks would you have

Sati [7]

The answer would be 331 weeks rounded. Just divide.

5 0

1 year ago

Among a simple random sample of 331 American adults who do not have a four-year college degree and are not currently enrolled in

Hitman42 [59]

Answer:

(1) Therefore, a 90% confidence interval for the proportion of Americans who decide to not go to college because they cannot afford it is [0.4348, 0.5252].

(2) We can be 90% confident that the proportion of Americans who choose not to go to college because they cannot afford it is contained within our confidence interval

(3) A survey should include at least 3002 people if we wanted the margin of error for the 90% confidence level to be about 1.5%.

Step-by-step explanation:

We are given that a simple random sample of 331 American adults who do not have a four-year college degree and are not currently enrolled in school, 48% said they decided not to go to college because they could not afford school.

Firstly, the pivotal quantity for finding the confidence interval for the population proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of Americans who decide to not go to college = 48%

n = sample of American adults = 331

p = population proportion of Americans who decide to not go to

college because they cannot afford it

Here for constructing a 90% confidence interval we have used a One-sample z-test for proportions.

So, 90% confidence interval for the population proportion, p is ;

P(-1.645 < N(0,1) < 1.645) = 0.90 {As the critical value of z at 5% level

of significance are -1.645 & 1.645}

P(-1.645 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 1.645) = 0.90

P( $-1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < $\hat p-p$ < $1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.90

P( $\hat p-1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < p < $\hat p+1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.90

90% confidence interval for p = [ $\hat p-1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ , $\hat p+1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ]

= [ $0.48 -1.96 \times {\sqrt{\frac{0.48(1-0.48)}{331} } }$ , $0.48 +1.96 \times {\sqrt{\frac{0.48(1-0.48)}{331} } }$ ]

= [0.4348, 0.5252]

(1) Therefore, a 90% confidence interval for the proportion of Americans who decide to not go to college because they cannot afford it is [0.4348, 0.5252].

(2) The interpretation of the above confidence interval is that we can be 90% confident that the proportion of Americans who choose not to go to college because they cannot afford it is contained within our confidence interval.

3) Now, it is given that we wanted the margin of error for the 90% confidence level to be about 1.5%.

So, the margin of error = $Z_(_\frac{\alpha}{2}_) \times \sqrt{\frac{\hat p(1-\hat p)}{n} }$

$0.015 = 1.645 \times \sqrt{\frac{0.48(1-0.48)}{n} }$

$\sqrt{n} = \frac{1.645 \times \sqrt{0.48 \times 0.52} }{0.015}$

$\sqrt{n}$ = 54.79

n = $54.79^{2}$

n = 3001.88 ≈ 3002

Hence, a survey should include at least 3002 people if we wanted the margin of error for the 90% confidence level to be about 1.5%.

5 0

1 year ago

A house is purchased for $300,000 and its value appreciates by 2.75% per year.In how many years will the house be worth $375,000

MArishka [77]

Answer:

In 9.09 years

Step-by-step explanation:

4 0

1 year ago

What is the 185th digit in the following pattern 12345678910111213141516

Delicious77 [7]

Answer:

The 185th digit following that pattern of '12345678910111213141516' would be the number '5'

Step-by-step explanation:

The reason the 185th digit is '5' is because the pattern increases it's standard number by the following number (ex, 1,2,3,4,5, etc), and eventually it reached 185 as one of it's numbers, '5' would be the digit because the '18' part of 185 would only be the 184th digit, hence you are needed to include the '5' to complete the sequence of that number to reach the 185th digit.

5 0

1 year ago