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jonny [76]
2 years ago
5

Ampicillin 250 mg IM every 12 hours is ordered. After reconstitution, there's 125 mg/mL. How many mL would you give?

Mathematics
1 answer:
Vanyuwa [196]2 years ago
4 0

Answer:

Correct choice is C. 2 mL.

Step-by-step explanation:

Given that Ampicillin 250 mg IM every 12 hours is ordered. After reconstitution, there's 125 mg/mL. Now we need to find about how many mL would you give.

Let number of ml needed = x.

Since ratio of mg per mL will be fixed so we get equation:

\frac{mL}{mg}=\frac{x}{250}=\frac{1}{125}

\frac{x}{250}=\frac{1}{125}

x=\frac{1}{125} \times 250

x=\frac{250}{125}

x=2

Hence correct choice is C. 2 mL.

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the diagonal of a tv is 26 inches long assuming that this diagonal forms a tv pair 30-60-90 right triangles what are the exact l
Alexxandr [17]
It is an application of Pythagorean Theorem

And it is clear that the lower angle is 30 and the apex angle is 60 (this is how always normal TVs look like) ... refer to the image I attached

So, to calculate the width and the length:

\frac{length}{26} =cos(30)\\~\\length=26*cos(30)=13 \sqrt{3} ~~in

\frac{width}{26} =sin(30)\\~\\width=26*sin(60)=13~~in


You can after that round the length to be 22.517 in



Hope you got the idea

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2 years ago
ΔABC is an equilateral triangle. m∠A = (3x - 12)°. Solve for x. A) 14 B) 19 C) 20 D) 24
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Answer:

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Step-by-step explanation:

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2 years ago
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Lyle graphs triangle ABC on coordinate axes. He performs two transformations on this figure that result in the congruent triangl
Shtirlitz [24]

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a rotation 90˚ clockwise and then a reflection across the y-axis

Step-by-step explanation:

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3 0
1 year ago
The length, l cm, of a simple pendulum is directly proportional to the square of its period (time taken to complete one oscillat
Greeley [361]

Answer:

1) L \propto T^2

Using the condition given:

2.205 m = K (3)^2

K = 0.245 \approx \frac{g}{4\pi^2}

So then if we want to create an equation we need to do this:

L = K T^2

With K a constant. For this case the period of a pendulumn is given by this general expression:

T = 2\pi \sqrt{\frac{L}{g}}

Where L is the length in m and g the gravity g = 9.8 \frac{m}{s^2}.

2) T = 2\pi \sqrt{\frac{L}{g}}

If we square both sides of the equation we got:

T^2 = 4 \pi^2 \frac{L}{g}

And solving for L we got:

L = \frac{g T^2}{4 \pi^2}

Replacing we got:

L =\frac{9.8 \frac{m}{s^2} (5s)^2}{4 \pi^2} = 6.206m

3) T = 2\pi \sqrt{\frac{0.98m}{9.8\frac{m}{s^2}}}= 1.987 s

Step-by-step explanation:

Part 1

For this case we know the following info: The length, l cm, of a simple pendulum is directly proportional to the square of its period (time taken to complete one oscillation), T seconds.

L \propto T^2

Using the condition given:

2.205 m = K (3)^2

K = 0.245 \approx \frac{g}{4\pi^2}

So then if we want to create an equation we need to do this:

L = K T^2

With K a constant. For this case the period of a pendulumn is given by this general expression:

T = 2\pi \sqrt{\frac{L}{g}}

Where L is the length in m and g the gravity g = 9.8 \frac{m}{s^2}.

Part 2

For this case using the function in part a we got:

T = 2\pi \sqrt{\frac{L}{g}}

If we square both sides of the equation we got:

T^2 = 4 \pi^2 \frac{L}{g}

And solving for L we got:

L = \frac{g T^2}{4 \pi^2}

Replacing we got:

L =\frac{9.8 \frac{m}{s^2} (5s)^2}{4 \pi^2} = 6.206m

Part 3

For this case using the function in part a we got:

T = 2\pi \sqrt{\frac{L}{g}}

Replacing we got:

T = 2\pi \sqrt{\frac{0.98m}{9.8\frac{m}{s^2}}}= 1.987 s

8 0
2 years ago
Which graph represents the compound inequality? –3 < n < 1
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