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2 years ago

What's .072 ÷ 345.00 is round to nearest tenth

Mathematics

2 answers:

elena55 [62]2 years ago

7 1

0.00020869565 - that is the whole answer, but if you were to round to the nearest tenth it would be 0.0

shusha [124]2 years ago

3 0

.072/345 being rounded to the nearest tenth is 0.00020869565.

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In a normally distributed data set a mean of 55 where 95% of the data fall between 47.4 and 62.6, what would be the standard dev

tresset_1 [31]

Answer:

The standard deviation of that data set is 3.8

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 55

95% of the data fall between 47.4 and 62.6. This means that 47.4 is 2 standard deviations below the mean and 62.6 is two standard deviations above the mean.

Using one of these points.

55 + 2sd = 62.6

2sd = 7.6

sd = 7.6/2

sd = 3.8

The standard deviation of that data set is 3.8

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2 years ago

A business buys invoice forms at a cost of $4.45 a box for the first 20 boxes, $4.00 a box for the next 25 boxes, and $3.75 a bo

Sergio039 [100]

So the first 20 boxes at 4.45 a piece will total 89.
The next 25 at 4 each will be 100.
Add those and you have 189 dollars, which is a spare of 45.
45/3.75 = 12 .
So the answer is 57

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2 years ago

The following table shows the annual income, in dollars, and amount spent on vacation, in dollars, for a sample of 8 families.

marishachu [46]

Answer:

a. Scatterplot is attached.

b. Positive Correlation

c. Correlation coefficient=0.9219

Step-by-step explanation:

The following procedure will be used to obtain the scatter plot

Open an Google Sheets file online or excel sheet on your computer.
In column B and C, enter the Income and Vacation data as provided above.
Select the data > click on insert CHART.
Chose Scatter Chart option

Click OK.

A scatter plot visualizing your data should be displayed as attached.

On your computer, open a spreadsheet in Google Sheets.
Double-click on your scatter plot.
At the right, click on Customize tab and then Series.
Scroll down and check the Trend line box

-From the trend line, your notice that your variables have a positive correlation.

-As the income increases, so does vacation expenditure.

c. The correlation coefficient can be calculated as follows.

Click on any empty cell in the sheet and enter the formula
"=CORREL((y-axis range),(x-axis range))"
ENTER

-From our Google Sheets calculation our variables have a positive correlation and the correlation coefficient is 0.9219

-The correlation coefficient,r can also be calculated manually:

-let x be income, and y be vacation and divide all the values by 100 to make the smaller and easier to manipulate:

$r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2-(\sum x)^2][n\sum y^2-(\sum y)^2}}\\\\\\\sum xy=153914\\\sum x=4485\\\sum y=246\\\sum x^2=2878447\\(\sum x)^2=4485^2=20115225\\(\sum y)^2=246^2=60516\\\sum y^2=8392\\n=8\\\\\#substitute \ and \ solve \ for \ r\\\\=\frac{8\times153914-4485\times 246}{\sqrt{[8\times 2878447-4485^2][8\times 8392-246^2]}}\\\\=0.92186\\\\\approx 0.9219$

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2 years ago

A sports company wants to package a ball with a 1.5-inch radius in sets of two. They have two options: a cylinder or a square pr

guajiro [1.7K]

Step 1

Find the Volume of the two balls

we know that

the Volume of a sphere is equal to

$V=\frac{4}{3} \pi r^{3}$

In this problem we have

$r=1.5\ in$

Substitute

$V=\frac{4}{3} \pi 1.5^{3}=4.5\pi\ in^{3}$

the volume of the two balls is equal

$V=2*4.5\pi=9 \pi\ in^{3}$

Step 2

Find the volume of a cylinder

we know that

The Volume of a cylinder is equal to

$V=\pi r^{2}h$

In this problem we have

$r=1.5\ in$

$h=4*r=4*1.5=6\ in$

Substitute

$V=\pi (1.5^{2})(6)=13.5 \pi\ in^{3}$

Step 3

Find the amount of wasted space in the cylinder

Subtract the volume of the two balls from the volume of the cylinder

$13.5\pi\ in^{3}-9\pi\ in^{3}=4.5\pi\ in^{3}=14.14\ in^{3}$

Step 4

Find the volume of the square prism

The volume of the prism is equal to

$V=Bh$

where

B is the area of the base of the prism

h is the height of the prism

In this problem we have

$B=(2*1.5)^{2}=9\ in^{2}$ -----> the base is equal to the diameter

$h=4*r=4*1.5=6\ in$

Substitute

$V=9*6=54\ in^{3}$

Step 5

Find the amount of wasted space in the prism

Subtract the volume of the two balls from the volume of the prism

$54\ in^{3}-9\pi\ in^{3}=25.73\ in^{3}$

Step 6

Compare the amount of wasted space

the amount of wasted space in the cylinder is $14.14\ in^{3}$

the amount of wasted space in the prism is $25.73\ in^{3}$

Find the difference

$25.73\ in^{3}-14.14\ in^{3}=11.59\ in^{3}=11.6\ in^{3}$

The package that has the least amount of wasted space is the cylinder

therefore

the answer is the option

the cylinder because it has approximately 11.6 in.3 less wasted space than the prism

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2 years ago

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The manager of a shopping mall distributed a customer-satisfaction survey by handing it to people as they came through one of th

Nina [5.8K]

Answer:

No. The results of the survey cannot be generalized to the population of all customers of the shopping mall.

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Survey results are biased, because data is collected from customers who came trough one specific door of the mall.

Some of the customers may be using some other door where satisfaction survey is not given to these people while passing the door.

Therefore survey results does not reflect thoughts of the population of all customers.

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2 years ago

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