This is just a basic proportion. 5/8 = x/12. So the 5 foot tall women would have a 7.5 foot shadow.
Answer:
59 accidents were investigated.
Step-by-step explanation:
The question above is a probability question that involves 2 elements: causes of accidents.
Let
A = Alcohol
E = Excessive speed
In the question, we are given the following information:
18 accidents involved Alcohol and Excessive speed =P(A ∩ E)
26 involved Alcohol = P(A)
12 accidents involved excessive speed but not alcohol = P( E ) Only
21 accidents involved neither alcohol nor excessive speed = neither A U B
We were given P(A) in the question. P(A Only) = P(A) - P(A ∩ E)
P(A Only) = 26 - 18
= 8
So, only 8 accident involved Alcohol but not excessive speed.
The Total number of Accidents investigated = P(A Only) + P( E only) + P(A ∩ E) + P( neither A U B)
= 8 + 12 + 18 + 21
= 59
Therefore, 59 accidents were investigated.
Hello.<span><span> </span><span>
<span><span>
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Let 2003 be the zero year; then 2005 is the three year, and 2008 the 5 year.
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P = ab^x
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P(3) = ab^3 = 800000
P(0) = ab^0 = 900000
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a = 900000
Solve for "b"::
b^3 = 8/9
b = 2/cbrt(9)
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Equation::
P(x) = 900000^x
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Ans: P(5) = 900000
Have a nice day</span></span></span></span>
Given that the<span> iq scores for large populations are centered at 100.
To get what percent of these 78 students have scores above 100 we conduct a normal distribution probability of the data.
P(x > 100) = P(z > (100 - 100)/sd) = P(z > 0) = 1 - P(z < 0) = 1 - 0.5 = 0.5 = 50%
</span>
<u>Given</u>:
Given that a circle O with two tangents BA and BC.
The major arc AC is 234°
The minor arc AC is 126°
We need to determine the measure of ∠ABC
<u>Measure of ∠ABC:</u>
We know the property that, "if a tangent and a secant, two tangents or two secants intersect in the interior of the circle, then the measure of angle formed is one half the difference of the measures of the intercepted arcs."
Hence, applying the above property, we have;
Substituting the values, we get;
Thus, the measure of ∠ABC is 54°
Hence, Option b is the correct answer.
