Because there isnt 90 degrees angle in this triangle (triangle - starting point - point where he starts climbing- ending point) we will use cosine law to find magnitude of displacement. For cosine law we need 2 sides of triangle and angle between them which is exactly what is given.
a^2 = b^2 + c^2 - 2*b*c*cos(alpha)
after expressing values we get:
a^2 = 10000 + 1225 + 5734
a = 130,2 meters
to calculate angle we again use cosine law but now our unknown variable is angle alpha. our sides we will use are 100 meters and 130,2 meters because we need angle between them.
cos(alpha) = (b^2 + c^2 - a^2)/(2*b*c)
cos(alpha) = 0.98
alpha = 8.89 degrees
Answer:
First, two lines are perpendicular if one has slope m, and the other has slope -1/m (Not 1m as Alan says)
That is the first error of Alan.
Now, there is another error.
If m = 0, then -1/m tends to minus infinity (in this case we would have a vertical line).
But we can not really divide by zero, so we should state that:
m can not be zero, if a line is horizontal, the perpendicular line must be vertical.
Answer:
Train b is moving faster than a by 45 units an hour
Step-by-step explanation:
<span>if we take the centre of the circle as being the origin, we can say that
x coordinate is :cos o = x/r so x
= r cos o
</span><span>
and
y coordinate : cos(90-teta)= y/r
so y=r*cos(90-teta)
</span><span>
if teta is 29 degrees
y=r*cos(61)
and
x = r * cos(29)</span>
The problem ask on which if the following is the value of M5 and M7 if transversal EF cuts parallel lines AB and CD as show in your diagram and the best answer would be letter D. m5 = 55.1 adn m7 =124.9. I hope you are satisfied with my answer and feel free to ask for more