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1 year ago

The segments shown below could form a triangle.

Mathematics

1 answer:

Rina8888 [55]1 year ago

5 0

Answer:

A. True

Step-by-step explanation:

The Triangle Inequality Theorem says that the sum of any two sides must be greater than the third side. Let's see if this is true.

a + b

9 + 1 = 10>9

a + c

9 + 9 = 18>1

c + b

9 + 1 = 10>9

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in the diagram below, <AFB = <EFD. if m<EFD = (5x+6)°, m<DFC = (19x-15)°, and m<EFC = (17x+19)°, find m<AFE

NeX [460]

Answer:

m<AFE = 128°.

Step-by-step explanation:

Step 1: Find the value of x

Angle EFD + Angle DFC = Angle EFC

5x + 6 + 19x - 15 = 17x + 19

24x - 9 = 17x + 19

7x = 28

x = 4

Step 2: Find all angles

Angle AFB=Angle EFD= 5x + 6

5(4) + 6 = 26°

Angle DFC = 19x - 15

19(4) - 15 = 61°

Step 3: Find angle AFE

Line BD is a straight line and all angles on a straight line are equal to 180°.

Angle AFB + Angle AFE + Angle EFD = 180°

26 + BFC + 26 = 180°

BFC = 180 - 52

BFC = 128°

Therefore, m<AFE is equal to 128°.

3 0

1 year ago

JL has coordinates J(-6, 1) and L(-4,3). Find the coordinates of the midpoint.

ikadub [295]

Answer:

The coordinates of the mid-point of JL are (-5 , 2)

Step-by-step explanation:

If point (x , y) is the mid-point of a segment whose end-points are $(x_{1},y_{1})$ and $(x_{2},y_{2})$ , then $x=\frac{x_{1}+x_{2}}{2}$ and $y=\frac{y_{1}+y_{2}}{2}$

∵ JL is a segment

∵ The coordinates of J are (-6 , 1)

∴ $x_{1}$ = -6 and $y_{1}$ = 1

∵ The coordinates of L are (-4 , 3)

∴ $x_{2}$ = -4 and $y_{2}$ = 3

Lets use the rule above to find the mid-point of JL

∵ $x=\frac{-6+-4}{2}=\frac{-10}{2}$

∴ x = -5

∴ The x-coordinate of the mid-point is -5

∵ $y=\frac{1+3}{2}=\frac{4}{2}$

∴ y = 2

∴ The y-coordinate of the mid-point is 2

∴ The coordinates of the mid-point of JL are (-5 , 2)

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2 years ago

A movie is 1 7/8 hours long. After 45 minutes, how much of the movie is left?

kolezko [41]

The answer is 1 1/8 hours left or 67.5 minutes!

3 0

1 year ago

Find b, given that a = 20, angle A = 30°, and angle B = 45° in triangle ABC

Kamila [148]

The side b is opposite to the angle B, applying the law of the sines, we have:

 $\frac{a}{sinA} = \frac{b}{sinB}$
$\frac{20}{sin30^0} = \frac{b}{sin45^0}$
$\frac{20}{ \frac{1}{2} } = \frac{b}{ \frac{ \sqrt{2} }{2} }$
$20* \frac{ \sqrt{2} }{2} = b* \frac{1}{2}$
$\frac{20 \sqrt{2} }{2} = \frac{b}{2}$
$2*b =2*20 \sqrt{2}$
$2b = 40 \sqrt{2}$
$b = \frac{40 \sqrt{2} }{2}$
$\boxed{b = 20 \sqrt{2} }$

6 0

1 year ago

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A customer hands you $3,850 in cash and would like to purchase 14 prepaid

Alecsey [184]

Answer:

thats kinda sus. his Id is expired. and you cant complete the transaction

Step-by-step explanation:

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1 year ago