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liubo4ka [24]
2 years ago
6

-3^(-x)-6=-3^x+10Solve the equation below for x by graphing plz

Mathematics
2 answers:
vitfil [10]2 years ago
8 0
To graph it, just graph y=-3^{-x}-6 and y=-3^x+10 and see where they intersect

I would like to solve it by using math and not graphing
if you don't want to see the math, just don't scroll down
the graphical meathod is above, first line, just read it

hmm
multiply both sides by -1
3^{-x}+6=3^x-10
multiply both sides by 3^x
3^0+6(3^x)=3^{2x}-10(3^x)
1+6(3^x)=3^{2x}-10(3^x)
minus 1 from both sides and minus 6(3^x) from both sides
0=3^{2x}-16(3^x)-1
use u subsitution
u=3^x
we can rewrite it as
0=u^2-16u-1
now factor
I mean use quadratic formula
for ax^2+bx+c=0 x=\frac{-b+/-\sqrt{b^2-4ac}}{2a}
so for 0=u^2-16u-1, a=1, b=-16, c=-1
u=\frac{-(-16)+/-\sqrt{(-16)^2-4(1)(-1)}{2(1)}
u=8+/-\sqrt{65}
remember that u=3^x so u>0
if we have u=8+√65, it's fine, but u=8-√65 is negative and not allowed
so therfor
u=8+\sqrt{65}=3^x
8+\sqrt{65}=3^x
if you take the log base 3 of both sides you get
log_3(8+\sqrt{65})=x
if you use ln then
ln(8+\sqrt{65})=xln(3)
then
\frac{ln(8+\sqrt{65})}{ln(3)}=x

nordsb [41]2 years ago
5 0

Answer:

x = 2.527

Step-by-step explanation:

We have to solve the equation -3^{-x}-6=-3^x+10 by graphing method.

In order to solve this equation from graphing method, we graph the below two equations in the same coordinate axes.

y=-3^{-x}-6...(i)\\\\y=-3^x+10...(ii)

The x -coordinate of the intersection point of these two graphs would be the solution of the equation.

Please see the attached graph.

The x-coordinate of the intersection point is 2.527.

Hence, the solution to the given equation is x = 2.527

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Which system of equations can be used to find the roots of the equation 12 x 3-5x=2 x 2+x+6
kirill [66]

Answer:

Option (a) is correct.

The system of equation becomes

y=12x^3-5x\\\\ y=2x^2+x+6

Step-by-step explanation:

Given : Equation  12x^3-5x=2x^2+x+6

We have to construct a  system of equations that  can be used to find the roots of the equation 12x^3-5x=2x^2+x+6

Consider the given equation 12x^3-5x=2x^2+x+6

To construct a system of equation put both sides of the given equation equal to a same variable.

Let the variable be "y", Then the equation 12x^3-5x=2x^2+x+6

becomes,

12x^3-5x=y=2x^2+x+6

Thus, The system of equation becomes

y=12x^3-5x\\\\ y=2x^2+x+6

Option (a) is correct.

   

8 0
2 years ago
Read 2 more answers
The perimeter of a triangle equals 8 inches. Two of its sides are equal and each of them is 1.3 inches bigger than the third sid
mafiozo [28]
Let's call the lengths of our two types of sides <em />x and y.

The two sides will that our 1.3 inches bigger than the third side will be have length x, and the length of the other side will be known as y. Thus, x = y + 1.3.

Considering this, we can add our sides together and set this value equal to 8, given the information in the problem:
(y + 1.3) + (y + 1.3) + y = 3y + 2.6 = 8

Now, let's solve for y.
3y + 2.6 = 8
3y = 5.4
y = 1.8

Now, we are not done yet. We must determine the true lengths of all of our sides. Using the equation we found earlier, the length of the two bigger sides is y + 1.3 = 1.8 + 1.3 = \boxed{3.1} inches and the length of our smaller side is simply \boxed{1.8} inches.

To verify, we can add these sides together and check that they equal 8:
3.1 + 3.1 + 1.8 = 8 ✔
5 0
2 years ago
Draw the unit circle with center (0,0)and plot the point P=(6,2). Observe there are TWO lines tangent to the circle passing thro
scZoUnD [109]

Answer:

Step-by-step explanation:

Given that a tangent is drawn from P (6,2) to unit circle with center at the origin.

The tangent passing through (6,2) would have equaiton of the form

y-6 = m(x-2)\\y =mx-2m+6 for suitable m.

Because this line is tangent, distance of centre of circle namely origin is the radius 1.

i.e. |\frac{-2m+6}{\sqrt{1+m^2} } |=1\\(-2m+6 )^2 = 1+m^2\\3m^2-24m+35=0\\\\m=1.918, 6.082

the coordinates are the intersection of the tangent with the circle

They are (-0.162, 0.987) and (0.462,-0.887)

8 0
2 years ago
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