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balandron [24]
1 year ago
6

15 PINTS!!!!!!!!! PLZ HELP!!!!!!!! The linear function f(x) = 0.5x + 80 represents the average test score in your math class, wh

ere x is the number of the test taken. The linear function g(x) represents the average test score in your science class, where x is the number of the test taken. x g(x) 1 81 2 83 3 85 Part A: Determine the test average for your math class after completing test 2. (2 points) Part B: Determine the test average for your science class after the completing test 2. (2 points) Part C: Which class had a higher average after completing test 4? Show work to support your answer. (6 points)
Mathematics
1 answer:
Stells [14]1 year ago
4 0

Answer:

Part A: The test average for the math class after completing 2 tests is 81

Part B: The test average for the science class after completing 2 tests is 83

Part C: The science class had the higher average test score after completing the test 4.

Step-by-step explanation:

The average test score for math class is given by the linear function, f(x) = 0.5·x + 80

The data for the average test score for science g(x) are;

x,   q(x)

1,     81

2,    83

3,    85

Part A: The average test score for math after completing test 2 is given as follows;

f(2) = 0.5×2 + 80 = 81

∴ The test average for the math class after completing 2 tests = 81

Part B:

The average test score for science after completing test 2 is given from the table as at x = 2, g(2) = 83

∴ The test average for the science class after completing 2 tests = 83

Part C: After completing 4 tests, we have for the math class, f(4) = 0.5×4 + 80 = 82

For the science class, it is observed that common difference between each subsequent test score average is 2, therefore, the average test score, for the fourth test is 2 added to the average test score after the third test, which gives;

Average test score, after completing the fourth test for the science class, g(4) = 85 + 2 = 87

Since g(4) > f(4) the science class had the higher average test score after completing the test 4.

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