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Serga [27]
2 years ago
13

Maria works as a ride loader on "Space Mountain". She averages twenty passengers every twenty minutes. Sal also works as a ride

loader on "Space Mountain" and averages twenty passengers every twenty-five minutes. If Maria and Sal work together, about how many minutes will it take to load twenty passengers?
Mathematics
1 answer:
Sati [7]2 years ago
3 0

Answer:

36 passengers

Step-by-step explanation:

Maria averages 20 passengers every 20 minutes, so she places 1 passenger per minute.

Sal averages 20 passengers every 25 minutes, so he places 0.8 passenger per minute.

If they work together, they can place (1 + 0.8) passengers = 1.8 passengers per minute.

In 20 minutes, they can load

1.8 passengers/minute * 20 minutes = 36 passengers

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The quality control manager at a light bulb factory needs to estimate the mean life of a batch (population) of light bulbs. We a
Nadusha1986 [10]

Answer:

<em>a)95%  confidence intervals for the population mean of light bulbs in this batch</em>

(325.5 ,374.5)

b)

<em>The calculated value Z = 4 > 1.96 at 0.05 level of significance</em>

<em>Null hypothesis is rejected </em>

<em>The manufacturer has not right to take the average life of the light bulbs is 400 hours.</em>

Step-by-step explanation:

Given sample size n = 64

Given  mean of the sample x⁻ = 350

Standard deviation of the Population σ = 100 hours

The tabulated value Z₀.₉₅ = 1.96

<em>95%  confidence intervals for the population mean of light bulbs in this batch</em>

<em></em>(x^{-} - Z_{\frac{\alpha }{2} } \frac{S.D}{\sqrt{n} } , x^{-} + Z_{\frac{\alpha }{2} }\frac{S.D}{\sqrt{n} } )<em></em>

<em></em>(350 - 1.96\frac{100}{\sqrt{64} } , 350 + 1.96\frac{100}{\sqrt{64} } )<em></em>

(350 -24.5, 350 +24.5)

(325.5 ,374.5)

b)

<u><em>Explanation</em></u>:-

Given mean of the Population μ = 400

Given sample size n = 64

Given  mean of the sample x⁻ = 350

Standard deviation of the Population σ = 100 hours

<u><em>Null hypothesis</em></u> : H₀:The manufacturer has right to take the average life of the light bulbs is 400 hours.

μ = 400

<u><em>Alternative Hypothesis: H₁:</em></u> μ ≠400

<u><em>The test statistic </em></u>

Z = \frac{x^{-}-mean }{\frac{S.D}{\sqrt{n} } }

Z = \frac{350 -400}{\frac{100}{\sqrt{64} } }

|Z| = |-4|

The tabulated value   Z₀.₉₅ = 1.96

The calculated value Z = 4 > 1.96 at 0.05 level of significance

Null hypothesis is rejected.

<u><em>Conclusion:</em></u>-

The manufacturer has not right to take the average life of the light bulbs is 400 hours.

5 0
2 years ago
Darcie wants to crochet a minimum of 3 blankets blankets to donate to a homeless shelter. Darcie crochets at a rate of 1/15 of a
bearhunter [10]

Answer:

The inequality to determine the number of days, s, Darcie can skip crocheting and still meet her goal is:

s\leq 15

Thus, Darcie can skip a maximum of 15 days.

Step-by-step explanation:

Question

Darcie wants to crochet a minimum of 3 blankets to donate to a homeless shelter. Darcie crochets at a rate of 1/15 of a blanket per day. She has 60 days until when she wants to donate the blankets, but she also wants to skip crocheting some days so she can volunteer in other ways. Write an inequality to determine the number of days, s, Darcie can skip crocheting and still meet her goal.

Given:

Darcie has a target to crochet a minimum of 3 blankets.

Rate at which Darcie crochets = \frac{1}{15} of a blanket per day.

Darcie has 60 days to crochet the blankets

To write an inequality to determine the number of days, s, Darcie can skip crocheting and still meet her goal.

Solution:

The number of days Darcie can skip crocheting is represented by s

So, number of days left for Darcie to crochet = 60-s

In 1 day Darcie crochets  \frac{1}{15} of a blanket.

So, in (60-s) days she will crochet = \frac{1}{15}(60-s)  blankets.

Her aim is to crochet at least 3 blankets.

Thus, the inequality can be given as:

\frac{1}{15}(60-s)\geq 3

Solving for s

Multiplying both sides by 15 to remove fractions.

15\times\frac{1}{15}(60-s)\geq 3\times 15

60-s\geq 45

Subtracting both sides by 60.

60-60-s\geq 45-60

-s\geq -15

Dividing both sides by -1.

\frac{-s}{-1}\leq \frac{-15}{-1}     [ On dividing by negative number the sign of the inequality is reversed]

∴ s\leq 15

Thus, Darcie can skip a maximum of 15 days.

3 0
2 years ago
Read 2 more answers
HELP PLEASE. Which regression equation best fits these data?
AlladinOne [14]

Answer:

B. y = -0.58x^2 -0.43x +15.75

Step-by-step explanation:

The data has a shape roughly that of a parabola opening downward. So, you'll be looking for a 2nd-degree equation with a negative coefficient of x^2. There is only one of those, and its y-intercept (15.75) is in about the right place.

The second choice is appropriate.

_____

The other choices are ...

A. a parabola opening upward

C. an exponential function decaying toward zero on the right and tending toward infinity on the left

D. a line with negative slope (This might be a good linear regression model, but the 2nd-degree model is a better fit.)

7 0
2 years ago
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Charlie wants to order lunch for his friends. He'll order 5 sandwiches and a $3 kid's meal for his little brother. Charlie has $
Dominik [7]
Inequality:
5x - 3 ≤ 28

Answer:
5x - 3 <span>≤ 28
5x </span><span>≤ 31
x </span><span>≤ 31/5 or 6.2 ($6.20)</span>
8 0
2 years ago
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Is 9760-5,220 more or less then 4,000
givi [52]
It's more than 4,000
7 0
2 years ago
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