Let the number of reserved tickets = x
Let the number of lawn seats = y
Constraint functions:
Maximum capacity means 
For concert to be held 
means 
Objective functions :
Maximum profit equation p = 65x +40y
Intersection points :
(10000,10000) (20000,0)(2500,2500)(5000,0)
p at (10000,10000) = 65(10000) + 40(10000) = $1050000
p at (20000,0) = 65(20000) + 40(0) = $1300000
p at (2500,2500) = 65(2500) + 40(2500) = $262500
p at (5000,0) = 65(5000) + 40(0) = $325000
Hence maximum profit occurs when all 20000 reserved seats are sold and the profit is $1300000
Please find attached the graph of it.
Answer:
y=-6/5+9
Step-by-step explanation:
your going ro put it in y=mx+b format
so it would be ur equation 12x+10y=90
subtract 12x from both sides and get 10y=-12x+90
u have to get 10 by itself so you divide 10 to everything and get y=-12/10x+90/10
you have to simplify so get y=-6/5+9
Let the width be w, length = 3w and height = 2w
Volume = length x width x height = w x 3w x 2w = 6w^3
6w^3 = 2,058
w^3 = 2,058/6 = 343
w = ∛343 = 7
width = 7 cm