Answer:
4589.75J
Step-by-step explanation:
Kinetic energy = 1/2 x M x v^2
Given
Mass M = 55.0kg
V = 12.92m/s
Kinetic energy
= 1/2 x 55.0 x (12.92)^2
= 1/2 x 55.0 x (12.92 x 12.92)
= 1/2 x 55.0 x 166.9
Multiply through
= 9179.5/2
= 4589.75J
Answer:
Probability that 32 or more from this sample used Internet Explorer as their browser is 0.9015.
Step-by-step explanation:
We are given that according to Net Market Share, Microsoft's Internet Explorer browser has 53.4% of the global market.
A random sample of 70 users was selected.
Let
= <u><em>sample proportion of users who used Internet Explorer as their browser.</em></u>
The z score probability distribution for sample proportion is given by;
Z =
~ N(0,1)
where, p = population proportion of users who use internet explorer = 53.4%
= sample proportion =
= 0.457
n = sample of users = 70
Now, probability that 32 or more from this sample used Internet Explorer as their browser is given by = P(
0.457)
P(
0.457) = P(
) = P(Z
-1.29)
= P(Z
1.29) = <u>0.9015</u>
The above probability is calculated by looking at the value of x = 1.29 in the z table which has an area of 0.9015.
Answer:
the installation fee is $104.40
Step-by-step explanation:
Solution:
Matte Satin Glossy Total
Homeowners 0.08 0.20 0.24 0.52
Contractors 0.04 0.26 0.18 0.48
Total 0.12 0.46 0.42 1
Approximately what percentage of contractors prefer the glossy finish?
Answer: Percentage of contractors who prefer the glossy finish is:
or 
Therefore, the option D. 37.5% is correct
Answer:
Step-by-step explanation:
From the information given, we would write the hypothesis.
For the null hypothesis,
H0 : µ = 70
For the null hypothesis,
Ha : µ > 70
This is a right tailed test because of the symbol of greater than.
The decision rule is to reject the null hypothesis if the level of significance is greater than the p value and accept the null hypothesis if the level of significance is lesser than the p value.
Therefore, since the significance level, 0.05 > p value, 0.01635, then we would reject the null hypothesis. There is enough evidence that the mean speed of all cars is greater than the posted speed limit of 70 mph.