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Nookie1986 [14]
1 year ago
15

$84 increased by 12% Use the percent of change to find the mew amount

Mathematics
1 answer:
11111nata11111 [884]1 year ago
7 0
84 increased by 12% of 84 = (1)84 + (0.12)84, or (1.12)84 = $94.08
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A 3-d printer was purchased for $20,000 and had a value of $12,000 after 2 years of use. assuming that the value is decreasing e
Mice21 [21]
 I think it is $13.33 dollars
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2 years ago
The total cost of a shirt and a tie was $75.62. if the price of the shirt was $4.02 less than the tie, what was the price of the
kifflom [539]
--------------------------------------------
Define x:
--------------------------------------------
Let the tie be x
Tie = x
Shirt = x - 4.02

--------------------------------------------
Construct equation :
 --------------------------------------------
The sum of the shirt and tie is $75.62
x + x -4.02 = 75.62
2x - 4.02 = 75.62
2x = 79.64
x = $39.82

--------------------------------------------
Find the cost of tie and shirt :
--------------------------------------------
Tie = x = $39.82
Shirt = x - $4.02 = $39.82 - $4.02 = $35.80

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Answer: The price of the short is $35.80
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5 0
1 year ago
Derrick needs to figure out how he’s doing on his test scores so far this year. You can help by calculating the mean and the med
romanna [79]

Answer:

74.4 ,81.5 , median

Step-by-step explanation:

ed20 answers

4 0
1 year ago
Read 2 more answers
A new curing process developed for a certain type of cement results in a mean compressive strength of 5000 kilograms per square
Sedbober [7]

Answer:

\alpha =0.0668

Step-by-step explanation:

Data given and notation  

The info given by the problem is:

n=25 the random sample taken

\mu =5000 represent the population mean

\sigma =100 represent the population standard deviation

The critical region on this case is \bar X so then if the value of \bar X \geq 4970 we fail to reject the null hypothesis. In other case we reject the null hypothesis

Null and alternative hypotheses to be tested  

We need to conduct a hypothesis in order to determine if the true mean is 5000, the system of hypothesis would be:  

Null hypothesis:\mu = 5000  

Alternative hypothesis:\mu \neq 5000  

Let's define the random variable X ="The compressive strength".

We know from the Central Limit Theorem that the distribution for the sample mean is given by:

\bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}})

Find the probability of committing a type I error when H0 is true.

The definition for type of error I is reject the null hypothesis when actually is true, and is defined as \alpha the significance level.

So we can define \alpha like this:

\alpha= P(Error I)= P(\bar X

And in order to find this probability we can use the Z score given by this formula:

Z=\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And the value for the probability of error I is givn by:

\alpha= P(\bar X

4 0
1 year ago
Machines A and B always operate independently and at their respective constant rates. When working alone, Machine A can fill a p
pychu [463]

Answer:

The value of x is \frac{10}{3} hours.

Step-by-step explanation:

Machine A = 5 hours

Machine B = x hours

Machine A and B = 2 hours

Using the formula: \frac{T}{A}  + \frac{T}{B} = 1

where:

T is the time spend by both machine

A is the time spend by machine A

B is the time spend by machine B

\frac{2}{5}  + \frac{2}{x}  = 1

Let multiply the entire problem by the common denominator (5B)

5x(\frac{2}{5}  + \frac{2}{x} = 1)

2x + 10 = 5x

Collect the like terms

10 = 5x - 2x

10 = 3x

3x = 10

Divide both side by the coefficient of x (3)

\frac{3x}{3}  = \frac{10}{3}

x = \frac{10}{3} hours.

Therefore, Machine B will fill the same lot in \frac{10}{3} hours.

7 0
1 year ago
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