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Paha777 [63]
1 year ago
15

Derrick needs to figure out how he’s doing on his test scores so far this year. You can help by calculating the mean and the med

ian to get an overall picture of his scores. Below are all of his scores: 25, 40, 68, 85, 95, 98, 70, 78, 85, 100 What is Derrick’s mean test score so far? What is Derrick’s median test score so far? Which gives a better picture of his scores?
Mathematics
2 answers:
romanna [79]1 year ago
4 0

Answer:

74.4 ,81.5 , median

Step-by-step explanation:

ed20 answers

patriot [66]1 year ago
3 0

Answer: Derrick’s mean test score= 74.4

Derrick’s median test score = 81.5

Better picture of his scores is given by Median.

Step-by-step explanation:

The given data : 25, 40, 68, 85, 95, 98, 70, 78, 85, 100

\text{Mean}=\dfrac{\text{Sum of all observations}}{\text{Number of observations}}\\\\\Rightarrow\ \text{Mean}=\dfrac{744}{10}=74.4

For Median , Arrange the data in order

25, 40, 68, 70, 78, 85, 85, 95, 98, 100

Median = Mean of two middle most value

\text{Median}=\dfrac{78+85}{2}=81.5

Since the data set has outlier (25) and mean is affected by outlier.

So the better picture of his scores given by median value.

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Two quadrilaterals are congruent. One has vertices P, N, O, and M, and the other has vertices S, T, V, and U. These correspondin
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Answer: NPOM \cong VUTS and OPNM \cong TVUS will be correct.

Explanation:

Given: two quadrilaterals having verticals P, N, O,M and S,T,V,U are congruent,  where, OM is congruent or equal to TS and \angle P\cong \angle U.

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since, the condition \angle P = \angle U

and, side UV=side  OM   follow for the above quadrilateral. (According to the figure)

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1 year ago
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1 year ago
On a certain​ route, an airline carries 7000 passengers per​ month, each paying ​$30. A market survey indicates that for each​ $
KengaRu [80]

Answer:

The ticket price that maximizes revenue is $50.

The maximum monthly revenue is $250,000.

Step-by-step explanation:

We have to write a function that describes the revenue of the airline.

We know one point of this function: when the price is $30, the amount of passengers is 7000.

We also know that for an increase of $1 in the ticket price, the amount of passengers will decrease by 100.

Then, we can write the revenue as the multiplication of price and passengers:

R=p\cdot N=(30+x)(7000-x)

where x is the variation in the price of the ticket.

Then, if we derive R in function of x, and equal to 0, we will have the value of x that maximizes the revenue.

R(x)=(30+x)(7000-100x)=30\cdot7000-30\cdot100x+7000x-100x^2\\\\R(x)=-100x^2+(7000-3000)x+210000\\\\R(x)=-100x^2+4000x+210000\\\\\\\dfrac{dR}{dx}=100(-2x)+4000=0\\\\\\200x=4000\\\\x=4000/200=20

We know that the increment in price (from the $30 level) that maximizes the revenue is $20, so the price should be:

p=30+x=30+20=50

The maximum monthly revenue is:

R(x)=(30+x)(7000-100x)\\\\R(20)=(30+20)(7000-100\cdot20)\\\\R(20)=50\cdot5000\\\\R(20)=250000

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