Question

Which table represents a linear function that has a slope of 5 and a y-intercept of 20? A 2-column table with 4 rows. Column 1 is labeled x with entries negative 4, 0, 4, 8. Column 2 is labeled y with entries 0, 20, 40, 60. A 2-column table with 4 rows. Column 1 is labeled x with entries negative 4, 0, 4, 8. Column 2 is labeled y with entries 0, negative 20, negative 40, negative 60. A 2-column table with 4 rows. Column 1 is labeled x with entries 0, 20, 40, 60. Column 2 is labeled y with entries negative 4, 0, 4, 8. A 2-column table with 4 rows. Column 1 is labeled x with entries negative 60, negative 40, negative 20, 0. Column 2 is labeled y with entries 8, 4, 0, negative 4.

Answer 1

Answer:

The 1st table represents a function

Step-by-step explanation:

* Lets explain how to solve the problem

- Function is a relation where each input has a single output

- The notation of the function is f(x) = y , where x is the input of the

 function and y is the out put of the function

-  The domain of the function is x and the range of the function is y

* Lets find which table represent a function

# First table:

     x      y

    -3      -1

     0      0

    -2      -1

- In the first table

∵ -3 has only -1

∵ 0 has only 0

∵ -2 has only -1

∵ 8 has only 1

∵ Every x has a single y

∴ The table represents a function

∴ The 1st table represents a function

- In the second table

   x       y

   -5       -5

    0       0

   -5       5

    6       -6

∵ x = -5 has y = -5 and y = 5

∴ One x has two values of y

∴ The table doesn't represent a function

- In the third table

    x          y

   -4         8

   -2         2

   -2         4

    0         2

∵ x = -2 has y = 2 and y = 4

∴ One x has two values of y

∴ The table doesn't represent a function

- In the fourth table

    x          y

   -4         2

    3         5

   -4         0

∵ x = -4 has y = 2 and y = 0

∴ One x has two values of y

∴ The table doesn't represent a function

Answer 2

Answer:

Its....

Step-by-step explanation:

The answer is a