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2 years ago

Joey's dog weighs 102.45 pounds. Jimmy's dog weighs 25.38 pounds less.

2 answers:

8 0

1.Since 5 is less than 8, borrow 1 from the next column to make 15.

2.Calculate 15 - 8, which is 7.

3.Calculate 3 - 3, which is 0.

4.Since 2 is less than 5, borrow 1 from the next column to make 12.

5.Calculate 12 - 5, which is 7.

6..Calculate 9 - 2, which is 7.

7.Therefore, 102.45 - 25.38 = 77.07.

prisoha [69]2 years ago

6 0

102.45 - 25.38 =77.07.

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There are 53 students on the Jackson Middle School basketball teams. The number of 8th graders is 15 fewer than three times the

pshichka [43]

Answer:

The number of 7th students on the Jackson Middle School basketball teams is 17 and the number of 8th students on the Jackson Middle School basketball teams is 36

Step-by-step explanation:

Let

x ----> the number of 7th students on the Jackson Middle School basketball teams

y ----> the number of 8th students on the Jackson Middle School basketball teams

we know that

There are 53 students on the Jackson Middle School basketball teams

$x+y=53$ -----> equation A

The number of 8th graders is 15 fewer than three times the number of 7th graders

$y=3x-15$ ----> equation B

substitute equation B in equation A

$x+(3x-15)=53$

solve for x

$x+3x=53+15\\4x=68\\x=17$

Find the value of y

$y=3(17)-15=36$

therefore

The number of 7th students on the Jackson Middle School basketball teams is 17 and the number of 8th students on the Jackson Middle School basketball teams is 36

6 0

2 years ago

Read 2 more answers

The telephone company is planning to introduce two new types of executive communications systems that it hopes to sell to its la

cluponka [151]

Answer:

x = 31 hundred dolars and

y = 91/2 = 45.5 hundred dolars

Step-by-step explanation:

Given

R(x) = (40−8x+5y)*x + (50+9x−7y)*y

C(x) = (40−8x+5y)*10 + (50+9x−7y)*29

We can use the equation

P(x) = R(x) - C(x)

where

P(x) is the profit

R(x) is the revenue

and C(x) is the costs

In order to maximize the telephone company's profit, we apply

P'(x) = R(x)' - C(x)' = 0

⇒ R(x)' = ((40−8x+5y)*x + (50+9x−7y)*y)' = (40x-8x²+14xy+50y-7y²)'

⇒ C(x)' = ((40−8x+5y)*10 + (50+9x−7y)*29)' = (1850+181x-153y)'

⇒ P'(x) = -8x²-7y²-141x+203y+14xy-1850

The first-order partial derivatives of these functions are

Px(x,y) = -16x-141+14y

Py(x,y) = -14y+203+14x

Setting these equal to zero and solving we obtain:

-16x+14y-141 = 0

14x-14y+203=0

we get the solution

x = 31 and y = 91/2 = 45.5

Finally, the company should produce 3100 units of the first system, and 4550 units of the second system.

8 0

2 years ago

Fabio is designing a flashlight that uses a parabolic reflecting mirror and a light source. The shape of the mirror can be model

ohaa [14]

Answer:

(2, 11/2)

Step-by-step explanation:

This is a vertical parabola; we know that because x is squared here, while y is not. The standard equation of a vertical parabola with vertex (h,k) is

4p(y-k) = (x-h)^2, where p is the distance between the vertex and the focus. Comparing

4p(y-k) = (x-h)^2 to

10(y-3) = (x-2)^2, we see that 4p = 10. Therefore, p = 10/4 = 5/2, which is the vertical distance between the focus and the vertex.

Since the coordinates of the vertex are easily read from the given equation

(x-2)^2=10(y-3): (h,k) = (2, 3)

all we need to do is to add p (5/2) to the y-coordinate (3);

The focus is at (2, 3 + 5/2), or (2, 11/2).

3 0

2 years ago

Find the indicated values: Given: OA=AC=2 AB is a tangent line Find: AB

nlexa [21]

Step-by-step explanation:

OA=AC=OC=2 (equal triangle)

which means angle O =60 degree

tan 60 = AB / 2

AB = 2 tan 60 =

$2 \sqrt{3}$

3 0

1 year ago

The scores of eighth-grade students in a math test are normally distributed with a mean of 57.5 and a standard deviation of 6.5.

Anna11 [10]

Approximately 68% of a normal distribution lies within one standard deviation of the mean, so this corresponds to students with scores between (57.5 - 6.5, 57.5 + 6.5) = (51, 64)

8 0

2 years ago

Read 2 more answers