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2 years ago

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Deondra has $12 to spend on a mixture of green and red grapes. What equation can she use to graph a line showing the different a

mounts of green and red grapes she can buy for $12?

1 answer:

Sonbull [250]2 years ago

6 0

Answer:

It depends on the cost of grapes.

Step-by-step explanation:

Half of 12 is 6, so if each pack of grapes cost 6 or less, she can buy a pack of green and red grapes.

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Ice cream usually comes in 1.5-quart boxes (48 fluid ounces), and ice cream scoops hold about 2 ounces. However, there is some v

Troyanec [42]

Answer:

(a) The expected value and standard deviation of the amount of ice cream served at the party are 54 ounces and 1.25 ounces respectively.

(b) The expected value and standard deviation of the amount of ice cream left in the box after scooping out one scoop are 46 ounces and 1.031 ounces respectively.

(c) Because the variance of each variable is dependent on the other.

Step-by-step explanation:

The random variable <em>X</em> and <em>Y</em> are defined as follows:

<em>X</em> = amount of ice cream in the box

<em>Y</em> = amount of ice cream scooped out

The information provided is:

E (X) = 48

SD (X) = 1

V (X) = 1

E (Y) = 2

SD (Y) = 0.25

V (Y) = 0.0625

(a)

The total amount of ice-cream served at the party can be expressed as:

<em>X</em> + 3<em>Y</em>.

Compute the expected value of (<em>X</em> + 3<em>Y</em>) as follows:

$E(X+3Y)=E(X)+3E(Y)\\= 48+(3\times2)\\=48+6\\=54$

Compute the variance of (<em>X</em> + 3<em>Y</em>) as follows:

$V(X+3Y) = V (X)+3^{2}V(Y)+2\times 3Cov (X,Y)\\=1+(9\times0.0625)+0\\=1.5625$

Then the standard deviation of (<em>X</em> + 3<em>Y</em>) is:

$SD(X + 3Y) =\sqrt{V(X + 3Y)}\\\sqrt{1.5625}\\=1.25$

Thus, the expected value and standard deviation of the amount of ice cream served at the party are 54 ounces and 1.25 ounces respectively.

(b)

The amount of ice-cream left in the box after scooping out one scoop is represented as follows:

<em>X</em> - <em>Y</em>.

Compute the expected value of (<em>X</em> - <em>Y</em>) as follows:

$E(X-Y)=E(X)-E(Y)\\=48-2\\=46$

Compute the variance of (<em>X</em> - <em>Y</em>) as follows:

$V(X - Y) =V(X)+V(Y)-2Cov(X,Y)\\=1+0.0625-0\\=1.0625$

Then the standard deviation of (<em>X</em> - <em>Y</em>) is:

$SD(X-Y) =\sqrt{V(X -Y)}\\\sqrt{1.0625}\\=1.031$

Thus, the expected value and standard deviation of the amount of ice cream left in the box after scooping out one scoop are 46 ounces and 1.031 ounces respectively.

(c)

The variance of the sum or difference of two variables is computed by adding the individual variances. This is because the variance of each variable is dependent on the others.

7 0

2 years ago

In circle N, KL ≅ ML. Circle N is shown. Line segments N J, N M, N L, and N K are radii. Lines are drawn to connect each point o

Sergeu [11.5K]

Answer:

$arc\ JM=132^o$

Step-by-step explanation:

The picture of the question in the attached figure

step 1

we know that

$arc\ JM+arc\ ML+arc\ LK+arc\ KJ=360^o$ ----> by complete circle

substitute the given values

$(13x+2)^o+(8x-3)^o+(7x+7)^o+(5x+24)^o=360^o$

solve for x

$(33x+30)^o=360^o\\33x=360-30\\33x=330\\x=10$

step 2

Find the measure of arc JM

$arc\ JM=(13x+2)^o$

substitute the value of x

$arc\ JM=(13(10)+2)^o=132^o$

8 0

2 years ago

Read 2 more answers

How do you do this?

Ray Of Light [21]

Thats a hardie gooks b

7 0

1 year ago

If a 10-pound turkey costs $20.42.how much does a 21-pound turkey cost

sergij07 [2.7K]

Answer:

$42.88

Step-by-step explanation:

Let's create a proportion using the following setup:

cost/pounds=cost/pounds

We know that it costs $20.42 for a 10 pound turkey.

$20.42/10 pounds= cost/pounds

We don't know how much a 21 pound turkey costs, so we can say that it costs $x for a 21 pound turkey.

$20.42/ 10 pounds= $x/ 21 pounds

20.42/10=x/21

We want to find x, by getting x by itself.

x is being divided by 21. The inverse of division is multiplication. Multiply both sides by 21.

21*(20.42/10)=(x/21)*21

21* 20.42/10=x

21*2.042=x

42.882=x

Round to the nearest cent, or hundredth.

42.88=x

x= $42.88

A 21 pound turkey costs $42.88

6 0

2 years ago

The score of golfers for a particular course follows a normal distribution that has a mean of 73 and a standard deviation of 3.

Artemon [7]

Answer:

P(X $\geq$ 74) = 0.3707

Step-by-step explanation:

We are given that the score of golfers for a particular course follows a normal distribution that has a mean of 73 and a standard deviation of 3.

Let X = Score of golfers

So, X ~ N( $\mu=73,\sigma^{2}=3^{2}$ )

The z score probability distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = population mean = 73

$\sigma$ = standard deviation = 3

So, the probability that the score of golfer is at least 74 is given by = P(X $\geq$ 74)

P(X $\geq$ 74) = P( $\frac{X-\mu}{\sigma}$ $\geq$ $\frac{74-73}{3}$ ) = P(Z $\geq$ 0.33) = 1 - P(Z < 0.33)

= 1 - 0.62930 = 0.3707

Therefore, the probability that the score of golfer is at least 74 is 0.3707 .

3 0

2 years ago