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Aleksandr [31]
2 years ago
5

Which statement follows from the given theorem? Theorem: The diagonal of a parallelogram divides it into two congruent triangles

.
A. Diagonals of a parallelogram bisect opposite angles.

B. Consecutive sides of a parallelogram are congruent.

C. Consecutive angles of a parallelogram are congruent.

D. Consecutive angles of a parallelogram are supplementary.
Mathematics
1 answer:
777dan777 [17]2 years ago
6 0

Answer with explanation:

Theorem : The diagonal of a parallelogram divides it into two congruent triangles.

Properties of parallelogram

1. Opposite sides are equal and parallel.

2. Diagonal bisect each other.

3. Opposite Angles are equal.

If you will look at the first three options

A:  Diagonals of a parallelogram bisect opposite angles.→→False(Alternate angles are equal)

B: Consecutive sides of a parallelogram are congruent.→→→False(Opposite sides are congruent)

C: Consecutive angles of a parallelogram are congruent.→→→False(Opposite angles are congruent)

D: Consecutive angles of a parallelogram are supplementary.→→→→True

For,any parallelogram, having vertices , A, B and C and D

Opposite sides are parallel, so

1.∠A + ∠B=180°

2.∠C + ∠B=180°

3.∠C+ ∠D=180°

4. ∠A + ∠D=180°

Option D

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2 years ago
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Step-by-step explanation:

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1 year ago
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What is 2 (log Subscript 3 Baseline 8 + log Subscript 3 Baseline z) minus log Subscript 3 Baseline (3 Superscript 4 Baseline min
Ilya [14]

Answer:

Value of expression in single logarithm is \log_3\left(2z^2\right).

Step-by-step explanation:

Given expression is,

2\left(\log_3\left(8\right)+\log_3\left(z\right)\right)-\log_3\left(3^4-7^2\right)

Now using logarithmic rule to solve the expression as follows,

Applying product rule of logarithmic,

\log_c\left(a\right)+\log_c\left(b\right)=\log_c\left(ab\right)

Therefore,

2\log_3\left(8z\right)-\log_3\left(3^4-7^2\right)

Applying power rule of logarithmic,

a\log_c\left(b\right)=\log_c\left(b^a\right)

Therefore,

\log_3\left(\left(8z\right)^2\right)-\log_3\left(3^4-7^2\right)

\log_3\left(\left(64z^2\right)\right)-\log_3\left(3^4-7^2\right)

Applying quotient rule of logarithmic,

\log_c\left(a\right)-\log_c\left(b\right)=\log_c\left(\frac{a}{b}\right)

Therefore,

\log_3\left(\dfrac{\left(64z^2\right)^2}{3^4-7^2}\right)

Simplifying,

\log_3\left(\dfrac{\left(64z^2\right)^2}{81-49}\right)

\log_3\left(\dfrac{\left(64z^2\right)^2}{32}\right)

\log_3\left(2z^2\right)

Therefore value of expression is \log_3\left(2z^2\right)

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Anon25 [30]

Answer:

16

Step-by-step explanation:

Subtracting the 2 expressions

3b² - 8 - b(b² + b - 7) ← distribute parenthesis

= 3b² - 8 - (b³  + b² - 7b) ← distribute parenthesis by - 1

= 3b² - 8 - b³ - b² + 7b ← collect like terms

= - b³ + 2b² + 7b - 8 ← substitute b = - 3 into the expression

= - (- 3)³ + 2(- 3)² + 7(- 3) - 8

= - (- 27) + 2(9) - 21 - 8

= 27 + 18 - 21 - 8

= 16

8 0
1 year ago
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