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masha68 [24]
2 years ago
8

In the diagram, the measurements that are labeled are known, while the other measurements are unknown. Which measurement of acut

e triangle ABC can you find by direct substitution of the labeled measures in the Law of Sines?
A.c

B.m/_C

C.m/_B

D.none

Mathematics
1 answer:
andrew-mc [135]2 years ago
8 0
As the sine rule states,

A/sina = B/sinb = C/sinc .

in the diagram, there are two identified sides and if you use the sine rule, you can find the opposed angles easily.

there are:

side a, with angle â .
side b, with angle b.

so the answer is C.

if you input these into the sine rule, it would be:

a/ sin a = b/sin b
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-12.48 -(-2.99)-5.62
KATRIN_1 [288]

Answer:

-15.11

Step-by-step explanation:

-12.48-(-2.99)-5.62=\\-12.48+2.99-5.62=\\-9.49-5.62=\\-15.11

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Para ingresar a la Universidad del Chocó se aplica una prueba de razonamiento que consta de 30 preguntas. Por cada respuesta cor
s2008m [1.1K]

Complete question:

Para ingresar a la Universidad del Chocó se aplica una prueba de razonamiento que consta de 30 preguntas. Por cada respuesta correcta se asignan 5 puntos y por cada incorrecta (o no contestada) se restan 2 puntos. Si un participante obtuvo un puntaje de 94 puntos, ¿cuantas preguntas respondió bien?

Responder:

número de respuestas correctas = 22

Explicación paso a paso:

Dado lo siguiente:

Número total de preguntas = 30

Deje respuestas correctas = y; Respuestas incorrectas = n

Marca otorgada por y = 5

Marca deducida por n = 2

Si el total de preguntas = 30; luego

y + n = 30 - - - - (1)

Puntuación total obtenida = 94; luego

5y - 2n = 94 - - - (2)

De 1),

y + n = 30

y = 30 - n

Sustituya y = 30 - n en equ (2)

5 (30 - n) - 2n = 94

150 - 5n - 2n = 94

150 - 7n = 94

-7n = 94-150

-7n = - 56

n = 56/7

n = 8

Sustituir n = 8 en (1)

y + n = 30

y + 8 = 30

y = 30 - 8

y = 22

y = número de respuestas correctas = 22

n = número de respuestas incorrectas = 8

3 0
2 years ago
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Answer:

box 1: monomial

box 2: binomial

Step-by-step explanation:

reasoning: Box 1’s volume is modeled by a monomial times a monomial, so it will be a monomial.

Box 2’s volume is modeled by a monomial times a binomial, so it will be a binomial.

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