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kondor19780726 [428]
1 year ago
13

Because you are working a late shift, you will get an increase in your wage. You will get and additional 10% per hour from 6:00p

m to 12:00 am and additional 15% from 12:00 am to 1:00 am
Mathematics
1 answer:
siniylev [52]1 year ago
7 0

CHECK THE COMPLETE QUESTION BELOW:

Supervisor: "Because you are working a late shift, you will get an increase in your wage. You will get an additional 10% per hour from 6:00 PM to 12:00 AM and additional 15% from 12:00 AM to 1:00 AM." Employee: "I am working from 2:00 PM to 12:00 AM. Between 2:00 PM and 6:00 PM, I will make $12.00 per hour. Between 6:00 PM and 12:00 AM, I will make __________ per hour

Answer:

I will make $13.2 per hour

Explanation:

It can be deducted from the question that that the money Employee gets money for Working from 2.00 PM to 6.00 PM = $12per hour

Also the Employee gets additional 10% of money for working from 6.00 PM to 12.00 AM which implies that

10% = (10/100)*$12per hour

=$1.2per hour

Again, Employee gets additional 15% of the money for working from 12.00 AM to 01.00 AM which can be calculated as:

15% = (15/100)*$12per hour

=$1.8 per hour

which means that Employee gets additional $1.8 per hour

of the money for working from 12.00 AM to 01.00 AM

Therefore, if Employee works from 2.00 PM to 12.00 AM,

Employee will gets money for Working from 2.00 PM to 6.00 PM as well as the 10\% extra wage which

= $12 + $1.2 = $13.2

= \$ 12 + \$ 1.2 = \$ 13.2

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Helen [10]

Answer:

0.46 (46%)

Step-by-step explanation:

We have the following data:

- Probability that player V wins the first set:

p(1)=0.50

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- Probability that player V wins the 2nd set if he has won the 1st set:

p(2|1)=0.60

So, the probability that player V wins the first 2 sets is:

p(12)=p(1)\cdot p(2|1)=(0.50)(0.60)=0.30 (1)

Instead, the probability that player V loses the 2nd set if he has won the 1st set is 0.40 (=1-0.60), so

p(2^c|1)=0.40

So, the probabiity that player V winse the 1st set but loses the 2nd set is

p(12^c)=p(1)\cdot p(2^c|1)=(0.50)(0.40)=0.20 (2)

Also, we have:

- Probability that player V loses the 1st set:

p(1^c)=0.50

- Probability that she will lose the 2nd set in this case is 0.70, it means that the probability that she will win the 2nd set if she lost the 1st set is 0.30, so:

p(2|1^c)=0.30

So, the probability that she will lose the 1st set and win the 2nd set is:

p(1^c2)=p(1^c)\cdot p(2|1^c)=(0.50)(0.30)=0.15 (3)

Combined together (2) and (3), this means that the probability that player V wins exactly 1 set out of the first two sets is:

p(1/2)=p(12^c)+p(1^c2)=0.20+0.15=0.35 (4)

At this point, the probability that she will win the 3rd set is

p(3)=0.45

This means that the overall probability that she will win the 3rd set if she won exacty 1 of the first 2 sets is:

p(1/2,3) = p(1/2)\cdot p(3)=(0.35)(0.45)=0.16 (5)

So, the overall probability that player V will win a match against player M is the sum of (1) and (5):

p(W)=p(12)+p(1/2,3)=0.30+0.16=0.46

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2 years ago
Describe the steps you used to solve the equation and find the amount of Carrie’s allowance. Linear equation:  1 4 a + 1 3 a + 8
Valentin [98]

Answer:

a = 0.519

Step-by-step explanation:

14a + 13a + 8 = 22

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a = 0.519

6 0
2 years ago
Read 2 more answers
RS=2x-8, ST= 11, RT= x+10
swat32

Answer:

X=7 ST=11 RT=17

Step-by-step explanation:

RT=RS+ST. RS= 2(7)-8. ST=11

X+10=2x-8+11. =14-8=6. RT= x+10

X+10=2x+3. RS=6. 7+10=17

10=x+3. RT=17

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Two new drugs are to be tested using a group of 60 laboratory mice, each tagged with a number for identification purposes. Drug
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Answer:

4.979044478499338 × 10²⁶

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Combination factorial is define by  ⁿCr = \frac{n!}{(n-r)!r!}

21 group of mice receiving Drug A  can be selected in ⁶⁰C₂₁ = \frac{60!}{21!39!}

(60 - 21 = 39 ) mice remained for selection of 21 mice for the second drug

Drug B 21 mice can be chosen with ³⁹C₂₁ = \frac{39!}{21!18!}

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If h(x) = 6 – x, what is the value of (h circle h) (10)?
Marta_Voda [28]

Answer:

10

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then

hoh(x) = x

then

hoh(10) = 10

5 0
1 year ago
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