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Norma-Jean [14]
2 years ago
10

a beach ball has a diameter of 18 inches. what is the approximate volume, rounded to the nearest whole number, of the Inflated b

each ball? Use 3.14 for pie A.) 24,417 in cube B.) 1,017 in cube C.) 9,156 in cube D.) 3,052 in cube
Mathematics
1 answer:
tino4ka555 [31]2 years ago
7 0
Hello!

A beach ball is in the shape of a sphere

To find the volume of a sphere you use the equation

V =  \frac{4}{3}  \pi  r^{3}

V is volume
r is radius

Put in the values you know and 3.14 for pi

V =  \frac{4}{3} * 3.14 *  18^{3}

Cube 18

V =  \frac{4}{3} * 3.14*5832

Multiply

V = 24416.64

Round to the nearest whole number

V = 24417

The answer is A)24,417

Hope this helps!
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sergejj [24]

Answer:

-40 < t < 284

Step-by-step explanation:

The antifreeze protects the car between −40°C and 140°C.

Using t for temperature, the compound inequality of the Celsius temperature range is:

-40 < t < 140

The conversion formula is given to find degrees C in given degrees F. We can solve the formula for F, so we get degrees F in terms of degrees C.

C = (5/9)(F - 32)     <------ <em>conversion formula from deg F to deg C</em>

Solve for F:

(9/5)C = F - 32

(9/5)C + 32 = F

F = (9/5)C + 32    <------ <em>conversion formula from deg C to deg F</em>

Now we convert -40 deg C to deg F using the formula we just derived.

F = (9/5)C + 32

F = (9/5)(-40) + 32

F = -72 + 32

F = -40

-40 deg C = -40 deg F

(This is not a mistake or a typo. -40 deg C really is the same as -40 deg F.)

Now we convert 140 deg C to deg F using the formula we just derived.

F = (9/5)C + 32

F = (9/5)(140) + 32

F = 252 + 32

F = 284

140 deg C = 284 deg F

Now we rewrite the compound inequality with Fahrenheit temperatures.

-40 < t < 284

4 0
2 years ago
An accident at an oil drilling platform is causing a circular-shaped oil slick to form. The volume of the oil slick is roughly g
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Answer:

V(t)=0.0112\pi t^{2}

Step-by-step explanation:

we have

V(r)=0.07\pi r^{2} -----> equation A

r(t)=0.4t -----> equation B

To find out (V of r)(t) substitute equation B in equation A

V(r(t))=V(t)

V(t)=0.07\pi (0.4t)^{2}

V(t)=0.07\pi (0.16)t^{2}

V(t)=0.0112\pi t^{2}

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inysia [295]
That might be a dilation but im not entirely sure
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