Question

ART A terracotta bowl artifact has a triangular pattern around the top, as shown. All the triangles are about the same size and can be
represented on a coordinate plane with vertices at points (0,6,8). (4.5,6,8), and (2.25,0). If each unit represents 1 centimeter, what is the
approximate perimeter of each triangle, to the nearest tenth of a centimeter?
cm
A

Answer 1

Answer: The approximate perimeter is 19cm

Step-by-step explanation:

We know the positon of the 3 vertices of our triangle.

(i do not know if the first point is (0.6, 8) or (0, 6.8), i wil use the second one).

The vertices are:

(0, 6.8)

(4.5, 6.8)

(2.25, 0)

The perimeter of a triangle is equal to the sum of the length of the 3 sides.

To find the distance between two points (a,b) and (c,d) we must calculate:

D = √( (a - c)^2 + (b - d)^2)

Then the 3 distances that we have are:

(0, 6.8) to (4.5, 6.8)

D1 = √( (0 - 4.5)^2 + (6.8 - 6.8)^2) = 4.5 cm

(0, 6.8) to (2.25, 0)

D2 = √( (0 - 2.25)^2 + (6.8 - 0)^2) = 7.02 cm

(2.25, 0) to (4.5, 6.8)

D3 = √( (2.25 - 4.5)^2 + (0 - 6.8)^2) = 7.02 cm

Then the perimeter, rounding to the nearest cm is:

7.02 cm + 7.02cm + 4.5 cm = 18.54cm

Now, as the first number after the decimal point is a 5, we should round up.

The approximate perimeter is 19cm