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2 years ago

(6/11) to the power 2 answer pls

Mathematics

2 answers:

allochka39001 [22]2 years ago

7 0

Answer:

Step-by-step explanation:

6/11^2 = 6/11 * 6/11 = 36 / 121.

You cannot simplify 36/121

Lana71 [14]2 years ago

5 0

Step-by-step explanation:

in fraction it comes 36/121

and in decimal.it comes 0.3

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What is StartFraction 11 Over 12 EndFraction divided by one-third? A fraction bar labeled 1. Under the 1 are 3 boxes labeled one

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Answer:

<h2>2 and three-fourths </h2>

Step-by-step explanation:

Given the expression $\frac{11}{12}/\frac{1}{3}$ , the equivalent expression can be gotten as shown;

$= \frac{11}{12}/\frac{1}{3}\\= \frac{11}{12}*\frac{3}{1}\\ = \frac{11}{4} \\= 2+\frac{3}{4}\\ = 2\frac{3}{4}$

2 and three-fourth therefore gives the required expression

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2 years ago

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Which of the following is not a congruence theorem or postulate A. SSA B. SAS C. AAS D. SSS

bixtya [17]

Answer:ITS A

Step-by-step explanation:

SAS: side angle side

SSA: is not a congruence theorem

AAS:angle angle side

SSS:side side side

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2 years ago

joanne cannot decide which of two washing machines to buy. The selling price of each is $660. The first is marked down by 40%.

Alexxx [7]

Answer: The first machine would cost $420

and the second machine would cost $432

you should buy the first machine

Step-by-step explanation:If you get a 30% discount, then you are paying 70% of the selling price.

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Machine 2: A 10% discount means you pay 90%

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2 years ago

Two forces, F1 and F2, are represented by vectors with initial points that are at the origin. The first force has a magnitude of

Strike441 [17]

Answer:

Step-by-step explanation:

The two force F1 and F2 are represented by vectors with initial points that are at the origin.

the terminal point of the vector is point P(1, 1, 0)

Therefore, the direction of the vector force is

$v_1=(1-0)\hat i+(1-0)\hat j +(0-0)\hat k\\\\=1\hat i+1\hat j+0\hat k\\\\=\hat i + \hat j$

The unit vector in the direction of force will be

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The magnitude of the force is 40lb, so the force will be

$F_1=40\times \frac{1}{\sqrt{2} } (\hat i+\hat j)\\\\=20\sqrt{2} (\hat i+\hat j)$

The terminal point of its vector is point Q(0, 1, 1)

Therefore, the direction of the vector force is

$v_2=(0-0)\hat i+(1-0)\hat j +(1-0)\hat k\\\\=0\hat i+1\hat j+1\hat k\\\\=\hat j + \hat k$

$\frac{v_2}{|v_2|} =\frac{\hat j+ \hat k}{\sqrt{0^2+1^2+1^2} } \\\\=\frac{1}{\sqrt{2} (\hat j +\hat k)}$

The magnitude of the force is 60lb, so the force will be

$F_2=60\times \frac{1}{\sqrt{2} } (\hat j+\hat k)\\\\=30\sqrt{2} (\hat j+\hat k)$

The resultant of the two forces is

$F=F_1+F_2\\\\=[20\sqrt{2} (\hat i+\hat j)]+[30\sqrt{2} (\hat j +\hat k)]\\\\=20\sqrt{2} \hat i+20\sqrt{2} \hat j +30\sqrt{2} \hat j+30\sqrt{2} \hat k\\\\=20\sqrt{2} \hat i+50\sqrt{2} \hat j+30\sqrt{2} \hat k$

The magnitude force will be

$|F|=\sqrt{(20\sqrt{2} )^2+(50\sqrt{2} )^2+(30\sqrt{2} )^2} \\\\=\sqrt{800+5000+1800} \\\\=\sqrt{3100} \\\\=55.68$

to (1 decimal place)=55.7lb

b) The direction angle of force F

The angle formed by F and x axis

$\alpha=\cos^{-1}(\frac{20\sqrt{2} }{\sqrt{3100} } )\\\\=\cos^{-1}(0.5080)\\\\=59.469$

The angle formed by F and y axis

$\alpha=\cos^{-1}(\frac{50\sqrt{2} }{\sqrt{3100} } )\\\\=\cos^{-1}(1.270)\\\\=$

The angle formed by F and z axis

$\alpha=\cos^{-1}(\frac{30\sqrt{2} }{\sqrt{3100} } )\\\\=\cos^{-1}(0.7620)\\\\=40.359$

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2 years ago

The picture below shows a box sliding down a ramp:

Gennadij [26K]

Answer:

$AC=15.1\ ft$

Step-by-step explanation:

we know that

In the right triangle ABC

The function sine of angle 68 degrees is equal to divide the opposite side SB by the hypotenuse AC

$sin(68\°)=\frac{AB}{AC}$

substitute the values and solve for AC

$sin(68\°)=\frac{14}{AC}$

$AC=\frac{14}{sin(68\°)}$

$AC=15.1\ ft$

4 0

2 years ago