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valentinak56 [21]
2 years ago
9

One pound of grapes costs $1.55. Which equation correctly shows a pair of equivalent ratios that can be used to find the cost of

3.5 pounds of grapes?
StartFraction 1.55 over 1 EndFraction = StartFraction x over 3.5 EndFraction
StartFraction 1.55 over 1 EndFraction = StartFraction 3.5 over x EndFraction
StartFraction 1 over 1.55 EndFraction = StartFraction x over 3.5 EndFraction
StartFraction x over 1.55 EndFraction = StartFraction 1 over 3.5 EndFraction
Mathematics
2 answers:
Shalnov [3]2 years ago
5 0

Answer:

StartFraction 1.55 over 1 EndFraction = StartFraction 3.5 over x EndFraction

Step-by-step explanation:

1 = 1.55

x = 3.5

1.55/1 =3.5/x

1.55/1 = 3.5/x correctly shows the equivalent ratios

miv72 [106K]2 years ago
4 0

Answer:

the answer is A i believe.

dont quote me on that thought

Step-by-step explanation:

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Barry also looks into the cost of repaying an easy access loan for $1000. The up-front cost of the loan is $3 for every $20 borr
natta225 [31]

Answer:

Barry has to pay back $1150

Step-by-step explanation:

We can set up an equation to help solve this problem

x is the amount he has to pay back

x=1000+3(1000/20)

1000/20 lets us know how many times he borrowed 20 dollars

x=1000+3(50)

x=1000+150

x=1150

Barry has to pay back $1150

3 0
2 years ago
Emily and a friend bought two tickets to see a soccer game. Each ticket cost $8.25. The friends paid a total of $24.50, which in
solniwko [45]
2\cdot8.25=16.5\\\\24.5-16.5=8\\\\8:2=4\\\\\frac{4}{8.25}\cdot100\%=\\\\\frac{400}{8.25}\%=\\\\48.48\%
6 0
2 years ago
Lisa the numbers least to greatest -2/5 -2.47 -2 1/2 5 21/4
Paraphin [41]

Answer:

least to greatest are:

-2.5, -2.47, -2/5, 5, 21/4

3 0
2 years ago
A specimen of aluminum having a rectangular cross section 10 mm 12.7 mm (0.4 in. 0.5 in.) is pulled in tension with 35,500 N (80
miskamm [114]

Answer:

\epsilon = 3.958\times 10^{-3}

Step-by-step explanation:

The Young's Module of Aluminium is E = 69\times 10^{9}\,Pa. The axial stress on the specimen is:

\sigma = \frac{F}{A_{t}}

\sigma = \frac{35500\,N}{(0.01\,m)\cdot (0.013\,m)}

\sigma = 2.731\times 10^{8}\,Pa

The strain is derived of following expression:

\epsilon = \frac{\sigma}{E}

\epsilon = \frac{2.731\times 10^{8}\,Pa}{69\times 10^{9}\,Pa}

\epsilon = 3.958\times 10^{-3}

4 0
2 years ago
Find all points on the circle (x^2) + (y^2) = 676 where the slope is 5/12
borishaifa [10]
Implicit defferentation

remember that dy/dx y= dy/dx


so
take derivitive of both sides
2x+2y \space\ \frac{dy}{dx}=0
solve for \frac{dy}{dx}
minus 2x both sides
2y \space\ \frac{dy}{dx}=-2x
divide both sides by 2y
\frac{dy}{dx}=\frac{-2x}{2y}
\frac{dy}{dx}=\frac{-x}{y}

when is the slope equal to \frac{5}{12}
solve for \frac{dy}{dx}=\frac{5}{12}
\frac{dy}{dx}=\frac{5}{12}
\frac{5}{12}=\frac{-x}{y}
5y=-12x
y=\frac{-12}{5}x
find where the circle and this line intersects

substitute \frac{-12}{5}x for y
x^2+(\frac{-12}{5}x)^2=676
x^2+\frac{144}{25}x^2=676
\frac{25}{25}x^2+\frac{144}{25}x^2=676
\frac{169}{25}x^2=676
times both sides by \frac{25}{169}
x^2=100
sqrt both sides, take positive and negative roots
x=+/-10

sub back

y=\frac{-12}{5}x
y=(\frac{-12}{5})(10) \space\ or \space\ (\frac{-12}{5})(-10)
y=\frac{-120}{5} \space\ or \space\ \frac{120}{5}
y=-24 \space\ or \space\ 24

the points are (10,-24) and (-10,24)
8 0
2 years ago
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