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Radda [10]
1 year ago
5

You were billed $28.50 for additional data usage on your cell phone at a rate of $9 per gigabyte. Three choices are correct ways

to calculate the additional gigabytes, g, that you used. Which choice is NOT?
Mathematics
1 answer:
Zepler [3.9K]1 year ago
4 0

Answer:

b.) 9/g = 28.5

Step-by-step explanation:

a.) 9g = 28.5

b.) 9/g = 28.5

c.) 28.5 = 9 x g

d.) 28.5/9 = g

Total billing = $28.50

Rate = $9 per gigabyte

Calculate the additional gigabytes, g, that you used.

Additional gigabyte used, g = Total billing / Rate

g = $28.50 / $9

9g = 28.50

28.50 = 9 × g

g = 28.50 / 9

Option b.) 9/g = 28.5 is the incorrect way to calculate the additional gigabytes, g, that you used.

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If t represent the number of tickets purchased for a baseball game, which scenario is modeled by the equation, 32.50t + 5 = 28.7
tino4ka555 [31]

Answer:

Replacing t with 4, 32.5*4 + 5 is 135 and 28.75 * 4 + 20 is also 135. Since these two are equal, the equation is verified.

or

If you substitute 4 for t in the equation, you get a true statement. That means it would cost the Burns family $135 for 4 tickets and parking for either lower-level or middle-level seats.

Step-by-step explanation:

4 0
2 years ago
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ABCD ~ EFGH<br> z=?<br> Please help me!!!
iragen [17]

Answer:

z = 110°

Step-by-step explanation:

Since the figures are similar, then corresponding angles are congruent, thus

∠H = ∠D, that is

z = 110°

5 0
2 years ago
A cooling tower for a nuclear reactor is to be constructed in the shape of a hyperboloid of one sheet. The diameter at the base
timurjin [86]

Answer:

Step-by-step explanation:

Equation for a hyperboloid of one sheet, with center at the origen and axis along z-axis is:

(x/a)²  +  (y/b)²   -  (z/c)²  =  1                         (1)

We have to find a , b, and c

We can express equation (1)

(x/a)²  +  (y/b)²    =  (z/c)² + 1                 (2)

Now if we cut the hyperboloid with planes parallel to xy plane we get for  z = k       ( K = 1 , 2 , 3  and so on ) circles of different radius

(x/a)²  +  (y/b)²    =  (k/c)² + 1

at z = k = 0 at the base of the hyperboloid  d = 300   or r = 150 m

we have

(x/a)²  +  (y/b)²   = 1      

x²  +  y²   =   a²                a² = (150)²       a = b = 150

and    x²  +  y²  = (150)²

Now the other condition is at 200 m above the base d = 500 m   r = 250 m  minimum diameter then in equation (2)  we have:

(x/a)²  +  (y/b)²    =  (z/c)² + 1        

(1/a)² [ x² + y² ]  = (z/c)² + 1  

but   x²  +  y²  = r²    and in this case   r  =  250 m  then

(250)²/(150)²   =  (z/c)² + 1    ⇒ (62500/ 22500)  =  (200/c)² + 1

2,78  =  40000/c² + 1

2.78c²  =  40000  + c²

1.78c² = 40000

c²  =  40000/1.78

c²  = 22471.91

c = 149,91

Then we finally have the equation:

x²/(150)²   + y² /(150)² - z²/149,91  = 1

7 0
2 years ago
Patricia can drive 36 kilometers for every 3 liters of gas she puts in her car
Anna35 [415]

Answer:

Patricia will run 132 kilometers with 11 liters of gas.

Step-by-step explanation:

The given table is representing the distance driven by Patricia for every liter of gas she puts in her car.

With 3 liters of gas she drives 36 kilometers.

This means in one liter of gas distance covered by the car = \frac{36}{3}=12 kilometers.

Similarly if the car runs 48 kilometers in 4 liters of gas then per liter distance covered by the gas will be = \frac{48}{4}=12 kilometers

Now with 11 liters of gas distance covered by the car will be = 11×12

= 132 kilometers

Therefore, with 11 liters of gas Patricia can run 132 kilometers.

3 0
2 years ago
Read 2 more answers
The amount of a sample remaining after t days is given by the equation P(t)=A(1/2)^(t/h), where A is the initial amount of the s
s344n2d4d5 [400]
The equation is:
P ( t ) = A * (1/2 )^(t/h)
If a sample contains 18% of the original amount of Radon - 222 and h = 3.8:
0.18 * A = A * ( 0.5 )^(t/3.8)   / : A ( we will divide both sides of the equation by A )
0.18 = ( 0.5 )^(t/3.8)
t/3.8 = log _{1/2}0.18
t / 3.8 = 2.47 ≈ 2.5
t = 3.8 * 2.5 = 9.5
Answer:
The best estimate for the age of the sample is 9.5 days.

5 0
2 years ago
Read 2 more answers
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