Answer:
The median is
Step-by-step explanation:
From the question we are told that
The sample size is n = 100
The
measurements is 
Generally since that after 0.900 we have 0.901 , then the

in the same manner the
,
Given that 0.902 was observed three times it means that
,
Given that 0.903 was observed two times it means that
,
Given that 0.903 was observed four times it means that
,
Given that the highest measurement is 0.958 then then the 
Generally the median is is mathematically represented as
![Median = \frac{ [\frac{n^{th}}{2}] + [(\frac{n}{2})^{th} + 1 ]}{2}](https://tex.z-dn.net/?f=Median%20%20%3D%20%20%5Cfrac%7B%20%5B%5Cfrac%7Bn%5E%7Bth%7D%7D%7B2%7D%5D%20%20%2B%20%5B%28%5Cfrac%7Bn%7D%7B2%7D%29%5E%7Bth%7D%20%2B%201%20%5D%7D%7B2%7D)
=> ![Median = \frac{ [\frac{100^{th}}{2}] + [(\frac{100}{2})^{th} + 1 ]}{2}](https://tex.z-dn.net/?f=Median%20%20%3D%20%20%5Cfrac%7B%20%5B%5Cfrac%7B100%5E%7Bth%7D%7D%7B2%7D%5D%20%20%2B%20%5B%28%5Cfrac%7B100%7D%7B2%7D%29%5E%7Bth%7D%20%2B%201%20%5D%7D%7B2%7D)
=> ![Median = \frac{ [50^{th}] + [51^{th} ]}{2}](https://tex.z-dn.net/?f=Median%20%20%3D%20%20%5Cfrac%7B%20%5B50%5E%7Bth%7D%5D%20%20%2B%20%5B51%5E%7Bth%7D%20%5D%7D%7B2%7D)
=>
=>
f (n + 1) = f(n) – 5 is the recursive formula can be used to generate the sequence below, where f(1) = 6 and n ≥ 1
<h3><u>Solution:</u></h3>
Given that,
f(1) = 6 and n ≥ 1
Given sequence is 6, 1, -4, -9, -14
<em><u>Let us first analyse the logic used in this sequence</u></em>
6 - 5 = 1
1 - 5 = -4
-4 - 5 = -9
-9 - 5 = -14
Thus the next terms in sequence are obtained by subtracting 5 from previous term
Thus a recursive formula can be formed as:
f (n + 1) = f(n) – 5
Where "n" is the nth term
Let us check our recursive formula:
f(1+ 1) = f(1) - 5
f(2) = f(1) - 5
f(2) = 6 - 5 = 1
Thus we have got f(2) = 1 which is correct as per given sequence
No it does NOT make sense to state density in kilograms per square meter. Density has to be stated in terms of mass per unit of volume and NOT per unit of area.
Answer:
10:30 am.
Step-by-step explanation:
We have been given that Ursula uses a printer that can print 12 pages per minute.
Ursula started printing flyer for an order yesterday. Today at 8 am she continued working on the order, and by 9 a.m. she had 420 flyers for the order completed. The order was to print 1500 pages.
Let us find the number of pages left to print.


To find the time it will take to print 1080 pages we will divide number of pages left to print by number of pages printed per minute.



90 minutes will be 1.5 hours , so 1.5 hours after 9 am will be 10:30 am. Therefore, the job was finished at 10:30 am.
Answer:
It is C -14r+6p
Step-by-step explanation:
If you want the explanation just tell me