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2 years ago

Select the correct image.

Mathematics

2 answers:

Anvisha [2.4K]2 years ago

6 0

Answer:

The BOTTOM LEFT ICE

Step-by-step explanation:

julia-pushkina [17]2 years ago

5 0

Answer: The ice image, bottom left.

Step-by-step explanation:

The albedo values give information about the proportion of radiation that a given object surfaces, for example, if an object has an albedo value of 0.2, this means that the object reflects 0.2*100% = 20% of the radiation.

You usually can see that darker objects have a smaller albedo value, while clearer objects have a bigger albedo value, meaning that as clearer is the color, usually it reflects a bigger proportion of the radiation.

Here we have that the bigger albedo value is in the ice ( 0.55), so the correct image is the ice image, at the bottom left.

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What are the coordinates of the circumcenter of this triangle? Enter your answer in the boxes.

Juliette [100K]

Answer:

(2,1)

Step-by-step explanation:

We can see that the given triangle.

The coordinates of A are (-1,5) .

The coordinates of B are (-1,-3).

The coordinates of C are (5,-3).

Distance formula: $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

AB= $\sqrt{(-3-5)^2+(-1+1)^2}=8$ units

BC= $\sqrt{(5+1)^2+(-3+3)^2}=6$ units

AC= $\sqrt{(5+1)^2+(-3-5)^2}=10$ units

Pythagoras theorem: $(Hypotenuse)^2=(Base)^2+(Perpendicular\;side)^2}$

$AB^2+BC^2=8^2+6^2=100$

$AC^2=(10)^2=100$

Therefore, $AC^2=AB^2+BC^2$

When a triangle satisfied the Pythagoras theorem then, the triangle is right triangle.

Hence, the given triangle is a right triangle.

We know that circum-center of right triangle is the mid point of hypotenuse.

Mid-point formula: $x=\frac{x_1+x_2}{2},y=\frac{y_1+y_2}{2}$

Using this formula then, we get

Mid-point of hypotenuse AC is given by

$x=\frac{-1+5}{2}=2,y=\frac{5-3}{2}=1$

Hence, the circum-center of triangle is (2,1).

7 0

2 years ago

Let P2 be the vector space of all polynomials of degree 2 or less, and let H be the subspace spanned by 10x2+4xâ1, 3xâ4x2+3, and

lord [1]

I suppose

$H=\mathrm{span}\{10x^2+4x-1,3x-4x^2+3,5x^2+x-1\}$

The vectors that span $H$ form a basis for $P_2$ if they are (1) linearly independent and (2) any vector in $P_2$ can be expressed as a linear combination of those vectors (i.e. they span $P_2$ ).

Independence:

Compute the Wronskian determinant:

$\begin{vmatrix}10x^2+4x-1&3x-4x^2+3&5x^2+x-1\\20x+4&3-8x&10x+1\\20&-8&10\end{vmatrix}=-6\neq0$

The determinant is non-zero, so the vectors are linearly independent. For this reason, we also know the dimension of $H$ is 3.

Span:

Write an arbitrary vector in $P_2$ as $ax^2+bx+c$ . Then the given vectors span $P_2$ if there is always a choice of scalars $k_1,k_2,k_3$ such that

$k_1(10x^2+4x-1)+k_2(3x-4x^2+3)+k_3(5x^2+x-1)=ax^2+bx+c$

which is equivalent to the system

$\begin{bmatrix}10&-4&5\\4&3&1\\-1&3&-1\end{bmatrix}\begin{bmatrix}k_1\\k_2\\k_3\end{bmatrix}=\begin{bmatrix}a\\b\\c\end{bmatrix}$

The coefficient matrix is non-singular, so it has an inverse. Multiplying both sides by that inverse gives

$\begin{bmatrix}k_1\\k_2\\k_3\end{bmatrix}=\begin{bmatrix}-\dfrac{6a-11b+19c}3\\\dfrac{3a-5b+2c}3\\\dfrac{15a-26b+46c}3\end{bmatrix}$

so the vectors do span $P_2$ .

The vectors comprising $H$ form a basis for it because they are linearly independent.

4 0

2 years ago

If a histogram of a sample of men's ages is skewed, what do you expect to see in the normal quantile plot?

Scorpion4ik [409]

Answer: Points are not following a straight-line pattern

Step-by-step explanation:

5 0

2 years ago

Yoki is running a 10-mile race. She runs at a steady speed and then slows down, stops to get a drink of water, and then runs fas

yawa3891 [41]

This is late, but for anyone searching the answer up in the future, the answer on Edg.enuity is the last one - where the graph starts out as a horizontal line, then decreases and touches the x-axis, then increases again.

Good luck on your assignment !!

4 0

2 years ago

Read 2 more answers

alice drew two triangles on the coordinate plane as shown. Which series of transformation proves the two triangles are congruent

Nimfa-mama [501]

Answer:

idk i just really neeed the points

Step-by-step explanation:

alice drew two triangles on the coordinate plane as shown. Which series of transformation proves the two triangles are congruent?

8 0

2 years ago