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IgorLugansk [536]
2 years ago
15

You could win a giant jar of jelly beans if only you could guess how many are in the jar. You find a smaller jar such that the g

iant one is exactly five times the smaller one in each dimension. If you count 83 jelly beans in your smaller jar, about how many should be in the giant jar?
Mathematics
2 answers:
Gennadij [26K]2 years ago
4 0

The giant jar of jelly beans is 5 times the size of the smaller jar. If there are 83 jelly beans in the smaller jar, the giant jar can be represented as 5(83).

5(83) = 415 jelly beans

KatRina [158]2 years ago
4 0

Answer: 415 jelly beans.

Step-by-step explanation:

Since, the ratio between the size of smaller jar and larger jar = 1 : 5

Thus, the ratio between the number of jellies contains by smaller and larger jar = 1 : 5

Let the jellies in smaller jar = x,

The jellies in larger jars = 5 x

Where x is any number.

According to the question,

The number of jellies in smaller jar = 83,

⇒ x = 83,

⇒ The number of jellies in larger jar = 5 x = 5 × 83 = 415

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If 2x + 5 = 8x, then 12x = ?
satela [25.4K]
X= 10

~because~

2x+5=8x, subtract 2x from both sides:

5=6x, divide 6 on both sides:

x=5/6, then rewrite the equation:

12(5/6)

x=10
6 0
2 years ago
Read 2 more answers
Conor has a roll of fence that is 25 feet long. He needs 8 yards of fence to go around a flower bed. Does he have enough fence t
vlabodo [156]

Answer:

Yes he has enough fence to go round the flower bed.

Step-by-step explanation:

1 yard = 3 feet

25 feet = 25/3 = 8.33 yards

Yes he has enough fence to go round the flower bed.

8 0
2 years ago
Joanna set a goal to drink more water daily. The number of ounces of water she drank each of the last seven days is shown below.
butalik [34]
(a) Data with the eight day's measurement.
Raw data:      [60,58,64,64,68,50,57,82], 
Sorted data:  [50,57,58,60,64,64,68,82]
Sample size = 8 (even)
mean            = 62.875
median         = (60+64)/2 = 62
1st quartile   = (57+58)/2 = 57.5
3rd quartile  = (64+68)/2 =  66
IQR = 66 - 57.5 = 8.5

(b) Data without the eight day's measurement.
Raw data:      [60,58,64,64,68,50,57]
Sorted data:  [50,57,58,60,64,64,68]
Sample size = 7 (odd)
mean            = 60.143
median         = 60
1st quartile   = 57
3rd quartile = 64
IQR = 64 -57 = 7

Answers:
1. The average is the same with or without the 8th day's data.  FALSE
2. The median is the same with or without the 8th day's data.  FALSE
3. The IQR decreases when the 8th day is included.                  FALSE
4. The IQR increases when the 8th day is included.                   TRUE
5. The median is higher when the 8th day is included.              TRUE

8 0
2 years ago
Read 2 more answers
A web server hosting company advertises 99.999 percent guaranteed network uptime. (a) how many independent network servers would
miv72 [106K]
The solution for this problem would be:
Given that there is 99.999%.

Let denote n as the network servers and p as the reliability of each server.
So the probability that the network uptime = 1 - (1 - p)^n

Therefore, (1-p) ^n = 0.00001


a. x= log(1-.99999)÷log(1-.97)= 3.2833 is the answer


1-(1-.97)^3= 0.99999 + 0.0001 = 1


b. x = log(1-.99999)÷log(1-.88) = 5.43 is the answer


1-(1-.88)^3= 0.99 + 0.0001 = approx 1
4 0
2 years ago
A middle school band has 45 sixth and seventh graders The ratio of sixth to seventh graders is 2 to 3 how many sixth graders are
AnnyKZ [126]

Answer:

  18

Step-by-step explanation:

There are 2+3 = 5 ratio units representing 45 band members, so each ratio unit represents 45/5 = 9 band members.

The 2 ratio units of sixth graders represent 2×9 = 18 sixth grade band members.

5 0
2 years ago
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