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IgorLugansk [536]
2 years ago
15

You could win a giant jar of jelly beans if only you could guess how many are in the jar. You find a smaller jar such that the g

iant one is exactly five times the smaller one in each dimension. If you count 83 jelly beans in your smaller jar, about how many should be in the giant jar?
Mathematics
2 answers:
Gennadij [26K]2 years ago
4 0

The giant jar of jelly beans is 5 times the size of the smaller jar. If there are 83 jelly beans in the smaller jar, the giant jar can be represented as 5(83).

5(83) = 415 jelly beans

KatRina [158]2 years ago
4 0

Answer: 415 jelly beans.

Step-by-step explanation:

Since, the ratio between the size of smaller jar and larger jar = 1 : 5

Thus, the ratio between the number of jellies contains by smaller and larger jar = 1 : 5

Let the jellies in smaller jar = x,

The jellies in larger jars = 5 x

Where x is any number.

According to the question,

The number of jellies in smaller jar = 83,

⇒ x = 83,

⇒ The number of jellies in larger jar = 5 x = 5 × 83 = 415

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Last year Lenny had an annual earned income of $58,475. He also had passive income of $1,255, and capital gains of $2,350. What
Lelechka [254]

<u>Answer:</u>  d. $62,080

<u>Step-by-step explanation:</u>

<u></u>

The capital gain is the profit earned from an investment whereas the passive income is the income generated by very minimal daily efforts.

Given: Annual income earned by Lenny = \$58,475

Passive income =  \$1,255

Capital gain =  \$2,350

Now,  \text{Total gross income =Annual income+Passive income+Capital gain}

=\$58,475+\$1,255+\$2,350=\$62,080

Hence, Lenny's total gross income for the year = $62,080

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1 year ago
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Jing spent 1/3 of her money on a pack of pens, 1/2 of her money on a pack of markers, and 1/8 of her money on a pack of pencils.
Reika [66]

As per the problem

Jing spent \frac{1}{3} of her money on a pack of pens.

\frac{1}{2} of her money on a pack of markers.

and \frac{1}{8} of her money on a pack of pencils.

Total fraction of money spent cab be given as below

Fraction of Money Spent =\frac{1}{3} +\frac{1}{2}+\frac{1}{8}

Take the LCD of denominator, we get LCD of (3,2,8)=24

Fraction of Money Spent =\frac{8+12+3}{24} =\frac{23}{24} \\\\

\\ \text{Hence fraction of Money Spent }=\frac{23}{24} \\ \\ \text{Fraction of Money left}=1-\frac{23}{24} \\ \\ \text{Simplify, we get}\\ \\ \text{Fraction of Money left}=\frac{24-23}{24} \\  \\ \text{Fraction of Money left}=\frac{1}{24}

3 0
2 years ago
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Round 545,999 to the nearest hundred thousand
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545,999 rounded to the nearest hundred thousand is 546,000.
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2 years ago
Which is most likely the correlation coefficient for the set of data shown?
mafiozo [28]

That's a really good positive correlation pictured.  The line fits the data very well.  The slope of the line is positive, meaning as x increases so does y.  I'd choose a big positive value.

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2 years ago
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The distribution of heights of a certain breed of terrier has a mean of 72 centimeters and a standard de- viation of 10 centimet
RSB [31]

Answer:

Pr(X-Y ≤ 44.2) = 0.5593

Step-by-step explanation:

for a certain breed of terrier

Mean(μ) = 72cm

Standard deviation (σ) = 10cm

n = 64

For a certain breed of poodle

Mean(μ) = 28cm

Standard deviation (σ) = 5cm

n = 100

Let X be the random variable for the height of a certain breed of terrier

Let Y be the random variable for the height of a certain breed of poodle

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= 44

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= √10^2/64 + 5^2/100

= √100/64 + 25/100

= √ 1.8125

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Using normal distribution,

Z= (X-Y- μx-y) / σx-y

Z= (44.2 - 44) / 1.346

Z= 0.2/1.346

Z= 0.1486

From the Z table, Z = 0.149 = 0.0593

Φ(z) = 0 0593

The probability that the difference of the observed sample mean is at most 44.3 is Pr(Z ≤ 44.2)

Recall that if Z is positive,

Pr(Z≤a) = 0.5 + Φ(z)

Pr(Z ≤ 44.2) = 0.5 + 0.0593

= 0.5593

Therefore,

Pr(X-Y ≤ 44.2) = 0.5593

5 0
2 years ago
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