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pantera1 [17]
2 years ago
9

Paul started work at company B ten years ago at the salary of $30,000. At the same time Sharla started at Company C at the salar

y of $36,000. Who earned more during the last year? How much more?
Mathematics
1 answer:
Naily [24]2 years ago
5 0

Answer:

Sharla has more, by $2000.

Step-by-step explanation:

Company B has 30000+2400x.

Company C has 36000+2000x.

Since we know x is equal to 10, because they have been working from the last ten years, we plug in 10 at where the x has been.

Company B: 30000+2400(10)

Company C: 36000+2000(10)

Let's first solve for B.

30000+2400(10)= 30000+24000=54000.

So, Paul earned $54000.

Next, Let's solve for C.

36000+2000(10)= 36000+20000=56000.

Sharla earned $56000.

It is obvious that sharla has more, so we will find the difference between the earnings of two companies.

56000-54000=2000.

So, Sharla has more earnings, with $2000 more than Paul.

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Determine whether each of these sets is finite, countably infinite, or uncountable. For those that are countably in- finite, exh
mrs_skeptik [129]

Answer:

a) the negative integers set A is countably infinite.

   one-to-one correspondence with the set of positive integers:

   f: Z+ → A, f(n) = -n

b) the even integers set A is countably infinite.

   one-to-one correspondence with the set of positive integers:

   f: Z+ → A, f(n) = 2n

c) the integers less than 100 set A is countably infinite.

   one-to-one correspondence with the set of positive integers:

   f: Z+ → A, f(n) = 100 - n

d) the real numbers between 0 and 12 set A is uncountable.

e) the positive integers less than 1,000,000,000 set A is finite.

f) the integers that are multiples of 7 set A is countably infinite.

   one-to-one correspondence with the set of positive integers:

   f: Z+ → A, f(n) = 7n

Step-by-step explanation:

A set is finite when its elements can be listed and this list has an end.  

A set is countably infinite when you can exhibit a one-to-one correspondence between the set of positive integers and that set.

A set is uncountable when it is not finite or countably infinite.

8 0
1 year ago
Billy's mother had five children. The first was named Lala, the second was named Lele, the third was named Lili, the fourth was
vovikov84 [41]

Answer:

billy

Step-by-step explanation:

its billy's mother. he/she is one of the children

4 0
2 years ago
Here are the vertices of rectangle FROG: (−2,5), (−2,1), (6,5), (6,1). Find the perimeter of this rectangle. If you get stuck, t
user100 [1]

Answer:

26

Step-by-step explanation:

Distance between (-2,5) and (-2,1) is 5

Distance between (-2,5) and (6,5) is 8

Distance between (6,5) and (6,1) is 5

Distance between (6,1) and (-2,1) is 8

5+8+5+8=26

5 0
1 year ago
Jordan wants to play a basketball game at a carnival. The game costs the player $5 dollar sign, 5 to play, and the player gets t
Alinara [238K]

Answer:

The expected value of Jordan gains is -1 dollar.

Step-by-step explanation:

Consider the following random variables. X := #of shots that Jordan makes. Then, we can can define the random variable Y of the earnings of Jordan in a game as follows

Y = 5 if X=2 (since he gets 10, but invested 5),  Y=0 if X=1(since he gets the 5 back) and Y=-5 if X=0(since he doesn't get the money back). Then, in this case, we can define the probability as follows.

P(Y=5) = P(X=2), P(Y=0) = P(X=1), P(Y=-5)= P(X=0).

By definition, the expected value of Y is given by

E[Y] = 5\cdot P(Y=5)+0\cdot P(Y=0)-5 P(Y=-5). By the previous analysis, we have that

E[Y] = 5\cdot P(X=2)-5P(X=0)

We only need to calculate the probabilities for X. In this case, we can consider each shot independt from each other. Then, we can consider X to be distributed as a binomial random variable with n=2 trials and p=0.4 of success (since he has a 40% chance of winning).

Then, by definition

P(X=k) = \binom{n}{k}p^k(1-p)^{n-k} = \binom{2}{k}0.4^{k}0.6^{2-k}

where \binom{n}{k}=\frac{n!}{k!(n-k)!}

Then,

P(X=0) = \frac{2!}{0!2!}0.4^{0}0.6^{2} = 0.36

P(X=2)=\frac{2!}{0!2!}0.4^{2}0.6^{0} = 0.16

Then,

E[Y] = 5\cdot 0.16-5\cdot 0.36 = -1

8 0
1 year ago
Mrs. Kermit has 29 markers. She gives 12 markers to Mr. Cooke and divides the rest among 5 other teachers. If each of the teache
romanna [79]

Answer: 2 markers.

Step-by-step explanation:

1. You know that she gives 12 markers to Mr. Cooke, then the rest among is:

29 markers-12 markers=17 markers

2. She divides the rest among 5 other teachers and each one of them get the same number of markers. So, you need to divide 17 markers by 5 teachers as following:

17 markers/5=3.4 markers

3. But the number of marker each one teacher has can't be a decimal number, so this number must be: 3 markers for each teacher.

3. The number of markers that will be left over is:

17 markers-(5*3 markers)=2 markers

8 0
2 years ago
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