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pantera1 [17]
2 years ago
9

Paul started work at company B ten years ago at the salary of $30,000. At the same time Sharla started at Company C at the salar

y of $36,000. Who earned more during the last year? How much more?
Mathematics
1 answer:
Naily [24]2 years ago
5 0

Answer:

Sharla has more, by $2000.

Step-by-step explanation:

Company B has 30000+2400x.

Company C has 36000+2000x.

Since we know x is equal to 10, because they have been working from the last ten years, we plug in 10 at where the x has been.

Company B: 30000+2400(10)

Company C: 36000+2000(10)

Let's first solve for B.

30000+2400(10)= 30000+24000=54000.

So, Paul earned $54000.

Next, Let's solve for C.

36000+2000(10)= 36000+20000=56000.

Sharla earned $56000.

It is obvious that sharla has more, so we will find the difference between the earnings of two companies.

56000-54000=2000.

So, Sharla has more earnings, with $2000 more than Paul.

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Solve for<br> a. 7a-2b = 5a b
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For this case we have the following expression:

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From here, we must clear the value of a.

We then have the following steps:

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