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max2010maxim [7]
2 years ago
15

The total load on a certain service is 525 kVA. One-third of this load is from motors; 3/5 is lighting; and 1/15 is from other l

oads. What is the kVA of each of these breakdowns of loads? Match with the correct answer shown below.
Mathematics
1 answer:
xxMikexx [17]2 years ago
5 0

Answer:

Motors 175 kVA

Lighting 315 kVA

Other loads 35 kVA

Step-by-step explanation:

The total load on a certain service is 525 kVA.

One-third of this load is from motors, then

\dfrac{1}{3}\cdot 525=175\ kVA

is from motors.

\frac{3}{5} is lighting, then

\dfrac{3}{5}\cdot 525=3\cdot 105=315\ kVA

is lighting.

\frac{1}{15} is from other loads, then

\dfrac{1}{15}\cdot 525=35\ kVA

is from other loads.

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You and two friends visit a pizza shop. There are 15 toppings. 5 toppings are meat and the rest are vegetable. Each of you order
viktelen [127]
Chance of u choosing meat is 5/15
first friend chooses, probability is 4/14
second friend chooses, probability is 3/13
so multiplying all 3 probablilities we get 2.2 percent
4 0
1 year ago
Jayden has some dimes and some quarters. He has at most 25 coins worth at least $4.60 combined. If Jayden has 7 dimes, determine
Y_Kistochka [10]

Answer:

Step-by-step explanation:

A dime is worth 10 cents. Converting to dollars, it becomes 10/100 = $0.1

A quarter is worth 25 cents. Converting to dollars, it becomes 25/100 = $0.25

Let x represent the number of dimes that Jayden has.

Let y represent the number of quarters that Jayden has.

Jayden has some dimes and some quarters. He has at most 25 coins. It means that

x + y ≤ 25

The coins worth at least $4.60 combined. It means that

0.1x + 0.25y ≥ 4.6 - - - - - - - - - - 1

If Jayden has 7 dimes, then

7 + y ≤ 25

y ≤ 25 - 7

y ≤ 18

Substituting x = 7 into equation 1, it becomes

0.1 × 7 + 0.25y ≥ 4.6

0.7 + 0.25y ≥ 4.6

0.25y ≥ 4.6 - 0.7

0.25y ≥ 3.9

y ≥ 3.9/0.25

y ≥ 15.6

All possible values for the number of quarters that he could have would be

15.6 ≤ y ≤ 18

6 0
2 years ago
Which system of equations below has no solution? A. y = 4x + 5 and y = 4x – 5 B. y = 4x + 5 and 2y = 8x + 10 C. y = 4x + 5 and y
Stels [109]

Answer: A  y=4x -5 and y=4x+5

Step-by-step explanation:

They have no solutions because they have the same slopes but different y intercepts. That works with any equation.

8 0
2 years ago
A manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 449 gram setting. It is
stealth61 [152]

Answer:

We accetp  H₀

Step-by-step explanation:

Information:

Normal distribution  

Population mean      =   μ₀  = 449

Population standard deviation  σ   unknown

Sample size   n  =  23        n < 30    we use t-student test

so   n  =  23    degree of fredom   df = n  - 1  df  = 23- 1   df = 22

Sample mean    μ =  448

Sample standard deviation   s  =  20

Significance level  α  =  0,05  

1.-Hypothesis Test

Null hypothesis                               H₀     μ₀  =  449

Alternative hypothesis                    Hₐ     μ₀  ≠  449

Problem statement ask for determine decision rule for rejecting the null hypothesis. For rejecting the null hypothesis we have to  get an statistic parameter wich implies  that μ is bigger or smaller than μ₀

2.-Significance level   α  =  0,05  ;  as we have a two tail test

α/2    =  0,025

Then from t - student table for  df =  22   and 0,025 (two tail-test)

t(c)  =  ±  2.074

3.- Compute  t(s)

t(s)   =  (  μ  -  μ₀ )  /  s /√n

plugging in values

t(s)   =  (448  -  449) /  20 /√23    ⇒   t(s)   =  -  1*√23 /20

t(s)   =  - 0.2398

4.-Compare t(c)   and  t(s)

t(s)  <  t(c)         - 0.2398  <  - 2.074

Therefore  t(s)  in inside acceptance region.  We accept  H₀

7 0
2 years ago
Say a certain service industry has 78.9 thousand jobs in 2003, but expects to increase at an average annual rate of 2.65 thousan
Alex_Xolod [135]

Answer:

33%

Step-by-step explanation:

In 2003, there were 78.9 thousand jobs in the industry and it increases annually by 2.65 thousand jobs from 2003 to 2013.

Hence, from 2003 to 2013, i.e. 10 years the jobs have increased by (2.65×10) = 26.5 thousand.

Therefore, the percent increase in jobs in the industry from 2003 to 2013 is given by \frac{26.5*100}{78.9} = 33.6 % ≈ 33%. (Answer)

4 0
2 years ago
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