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2 years ago

11

A charity is holding a benefit at an italian restaurant. The owner of the restaurant offers to donate $200 in addition to $4 for

each person that attends. If 46 people attend,how much with the owner donate?

2 answers:

Bingel [31]2 years ago

6 0

So it's $4 for 46 people.
4×46=184
And then add the additional $200.

184+200=384

the owner will donate $384.

Paraphin [41]2 years ago

4 0

$200 + {4 \times 46}$

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The answer is C.
Step-by-step explanation:
Given Naoma draws a portion of a figure as shown. She wants to construct a line segment through R that makes the same angle with QR as PQ.
To draw the line we will make sure to draw the same angle as that of the angle between QR and PQ.
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2 years ago

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A computer virus is trying to corrupt two files. The first file will be corrupted with probability 0.4. Independently of it, the

Ksivusya [100]

Answer:

$P(X = 0) = 0.42$

$P(X = 1) = 0.46$

$P(X = 2) = 0.12$

Step-by-step explanation:

We have these following probabilities:

40% probability that the first file is corrupted. So 60% probability that the first file is not corrupted.

30% probability that the second file is corrupted. So 70% probability that the second file is not corrupted.

Probability mass function

Probability of each outcome(0, 1 and 2 files corrupted).

No files corrupted:

60% probability that the first file is not corrupted.

70% probability that the second file is not corrupted.

So

$P(X = 0) = 0.6*0.7 = 0.42$

One file corrupted:

First one corrupted, second no.

40% probability that the first file is corrupted.

70% probability that the second file is not corrupted.

First one ok, second one corrupted.

60% probability that the first file is not corrupted.

30% probability that the second file is corrupted.

$P(X = 1) = 0.4*0.7 + 0.6*0.3 = 0.46$

Two files corrupted:

40% probability that the first file is corrupted.

30% probability that the second file is corrupted.

$P(X = 2) = 0.4*0.3 = 0.12$

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2 years ago

A factory makes propeller drive shafts for ships. A quality assurance engineer at the factory needs to estimate the true mean le

borishaifa [10]

Answer:

$1000-1.96\frac{2}{\sqrt{4}}=998.04$

$1000+1.96\frac{2}{\sqrt{4}}=1001.96$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that $z_{\alpha/2}=1.96$

Now we have everything in order to replace into formula (1):

$1000-1.96\frac{2}{\sqrt{4}}=998.04$

$1000+1.96\frac{2}{\sqrt{4}}=1001.96$

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2 years ago

Liz and Andy make money selling jewelry at a local fair. Liz and Andy both sell necklaces for $8 each. Andy also sells bracelets

Gelneren [198K]

Equation for Liz:

L = 8n

Equation for Andy:

A = 8n + 35

Step-by-step explanation:

Let the no. of necklace be 'n'

Cost per necklace= $8

Equation for Liz:

L = 8n

Because Liz sells only necklace for $8 each

Equation for Andy:

A = 8n + 35

Because Andy sells each necklace for $8 and she sold the bracelets for $35

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2 years ago

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A doctor is measuring the average height of male students at a large college. The doctor measures the heights, in inches, of a s

amid [387]

Answer:

The correct conclusion is:

<em>"The doctor can be 95% confident that the mean height of male students at the college is between 63.5 inches and 74.4 inches."</em>

Step-by-step explanation:

A doctor is measuring the average height of male students at a large college.

The doctor measures the heights, in inches, of a sample of 40 male students from the baseball team.

Using this data, the doctor calculates the 95% confidence interval (63.5, 74.4).

The following conclusions is valid:

<em>"The doctor can be 95% confident that the mean height of male students at the college is between 63.5 inches and 74.4 inches."</em>

Since we know that the confidence interval represents an interval that we can guarantee that the target variable will be within this interval for a given confidence level.

For the given case, the confidence level is 95% and the corresponding confidence interval is (63.5, 74.4) which represents the true mean of heights for male students at the college where the doctor measured heights.

Therefore, it is valid to conclude that the doctor is 95% confident that the mean height of male students at the college is within the interval of (63.5, 74.4).

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2 years ago