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valina [46]
2 years ago
15

Triangle BAC was rotated 90° clockwise and dilated at a scale factor of 2 from the origin to create triangle XYZ. Based on these

transformations, which statement is true?
coordinate plane with triangles ACB and XYZ with A at negative 4 comma 4, C at negative 1 comma 3, B at negative 4 comma 0, X at 0 comma 8, Y at 8, comma 8, and Z at 6 comma 2


∠C ≅ ∠X

∠C ≅ ∠Y

∠A ≅ ∠Y

∠A ≅ ∠X

Mathematics
2 answers:
ANEK [815]2 years ago
8 0

Answer:

The correct option is;

∠A ≅ ∠X

Step-by-step explanation:

The given coordinates of the points of triangle ACB are;

A(-4, 4), C(-1, 3), B(-4, 0)

The given coordinates of the points of triangle XYZ are;

X(0, 8), Y(8, 8), Z(6, 2), therefore, we have

The length. l. of segment is given by the following formula;

l = \sqrt{\left (y_{2}-y_{1}  \right )^{2}+\left (x_{2}-x_{1}  \right )^{2}}

For the length of the segment AC; (x₁, y₁) = (-4, 4), (x₂, y₂) = (-1, 3), l = √(10)

For the length of the segment AB; (x₁, y₁) = (-4, 4), (x₂, y₂) = (-4, 0), l = 4

For the length of the segment BC; (x₁, y₁) = (-4, 0), (x₂, y₂) = (-1, 3), l = 3·√2

For the length of the segment XY; (x₁, y₁) = (0, 8), (x₂, y₂) = (8, 8), l = 8

For the length of the segment XZ; (x₁, y₁) = (0, 8), (x₂, y₂) = (6, 2), l = 6·√2

For the length of the segment ZY; (x₁, y₁) = (6, 2), (x₂, y₂) = (8, 8), l = 2·√(10

Therefore;

XY ~ AB, XZ ~ BC, ZY ~ AC

Which gives;

∠A ≅ ∠X, ∠B ≅ ∠Y, ∠C ≅ ∠Z

kompoz [17]2 years ago
7 0

Answer: D) ∠A ≅ ∠X is the true statement.

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Find the missing term in the following sequence ? 1, 4, 11, 26, 57, 120, ______
Marysya12 [62]

Answer:

247

Step-by-step explanation:

1,4,11,26,57,120. see the pattern that emerges from the series:

4–1 = 3; 3–1 = 2 = 2^1

11–4 = 7; 7 - 3 = 4 = 2^2

26 - 11 = 15; 15 - 7 = 8 = 2^3

57 - 26 = 31; 31 - 15 = 16 = 2^4

120 - 57 = 63; 63 - 31 = 32 = 2^5

so the next number should be 64+63 = 127+120 = 247.

check: 247–120 = 127; 127–63 = 64 = 2^6. correct.

so the next number is 247. 2^n+(n-1)

5 0
2 years ago
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Evaluate log4 0.25 ?
Vsevolod [243]

Answer:

-1

Step-by-step explanation:

Recall that 0.25 = 1/4, and that 1/4 = 1/[4^(-1)  Notice that 4 is the base of this log system.

Then log4 0.25 = log4(1/4) = log4(4^(-1) ) = -1 (answer)

Check:  Does 4^(-1) = 0.25?  Yes

8 0
2 years ago
Salmon often jump waterfalls to reach their breeding grounds. One salmon starts 2.00m from a waterfall that is 0.55m tall and ju
Law Incorporation [45]

Answer: 6.2 m/s

Explanation:

1) This is a projectile motion (parabolic)

2) Velocity:

i) initial velocity = V₀

ii) Horizontal component:

V₀x = V₀ cos α

The horizontal velocity is constant, so Vx = V₀x

ii) Vertical component:

V₀y = V₀ sin α

The vertical component is linear with acceleration = g ≈ 9.8 m/s²

Vy = V₀y - gt = V₀ sin α - gt

3) Displacement equations

i) Horizontal displacment:

x = V₀ cosα t

ii) Vertical displacement:

y = V₀ sin α t - g t² / 2

y ≈ V₀ sin α t - 4.9 t²

4) Solution

i) x = V₀ cosα t = V₀ cos(32°) t = 2.00 m ← salmon starts 2.00m from a waterfall

⇒ V₀ = 2 / [cos(32°) t ]

ii) y = V₀ sin α t - 4.9 t² = V₀ sin(32°) t - 4.9 t²

iii) Replace V₀ with 2 / [cos(32°) t ]

y = sin(32°) × 2 / [cos(32°) t ] × t - 4.9t² = 2 tan(32°) - 4.9t²

iv) Use jump's height (y = 0.55m) and solve

⇒ 0.55 = 2 tan(32°) - 4.9t²

t² = [2 tan(32°) - 0.55 ] / 4.9 = 0.143 s²

⇒ t = √ (0.143s²) = 0.38 s

v) Use V₀ = 2 / [cos(32°) t ] to find V₀

V₀ = 2 / [cos(32°) (0.38) ] = 6.2 m/s

8 0
2 years ago
Read 2 more answers
Please help me answer this ASAP! The two-way table shows the number of ninth and tenth graders who prefer going to sporting even
Elis [28]
<h2>Answer</h2>

0.43

<h2>Explanation</h2>

Remember that RelativeFrecuency=\frac{Frecuency}{SumOfAllFrecuencies}

Since the problem is telling us "Among tenth graders", we must focus on the 10th graders row only. From the row, we can infer that the frequency is the number of 10th graders who prefer going to sporting events, so Frecuency=6. Now, the sum of all frequencies will be the sum of all the 10th graders, so SumOfAllFrecuencies=6+8=14. Let's replace the values:

RelativeFrecuency=\frac{Frecuency}{SumOfAllFrecuencies}

RelativeFrecuency=\frac{6}{14}

RelativeFrecuency=0.4285

And rounded to the nearest hundredth:

RelativeFrecuency=0.43

4 0
2 years ago
A bank account earned 3.5% continuously compounded annual interest. After the initial deposit, no deposits or withdrawals were m
aalyn [17]

This question is incomplete. Below is the complete question:

A bank account earned 3.5% continuously compounded annual interest. After the initial deposit, no deposits or withdrawals were made. At the end of an 8 year period, the balance in the account was $13231.30. what is the amount of the initial deposit?

Answer: The initial deposit is $10,001

Step-by-step explanation:

To solve this we need to utilize the continuous compounding interest formula:-

Fv = Pv × e^(i × t)

Where, Fv = the future value

Pv = present value

i = the interest rate

t = the time in years

e = a mathematical constant that is usually approximated by 2.7183

In this case, the Fv = 13,231.30

i = 3.5% or 0.035

t = 8 years

e = 2.7183

Pv = ? (The unknown variable).

13,231.30 = Pv × [2.7183^(0.035 × 8)]

13,231.30 = Pv × [2.7183^(0.28)]

13,231.30 = Pv × 1.323

Pv = 13,231.30/1.323

Pv = $10000.98

= $10,001

Therefore the initial deposit is $10,001

8 0
2 years ago
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