If a pack of paper costs 3.75 including tax, and there is a $20 budget, then the equation to find out the answer would be 3.75p is greater or equal to $20. So the answer would be B. 3.75 would be multiplied by the tax and then applied up to $20.
Answer:
The probability of getting a sample with 80% satisfied customers or less is 0.0125.
Step-by-step explanation:
We are given that the results of 1000 simulations, each simulating a sample of 80 customers, assuming there are 90 percent satisfied customers.
Let 
= <u><em>sample proportion of satisfied customers</em></u>
The z-score probability distribution for the sample proportion is given by;
Z = 
~ N(0,1)
where, p = population proportion of satisfied customers = 90%
n = sample of customers = 80
Now, the probability of getting a sample with 80% satisfied customers or less is given by = P( 
80%)
P( 80%) = P( 
) = P(Z -2.24) = 1 - P(Z < 2.24)
= 1 - 0.9875 = <u>0.0125</u>
The above probability is calculated by looking at the value of x = 2.24 in the z table which has an area of 0.9875.
There are two triangles that exist in this problem. First is the given triangle ABC, witch AB = BC = 6 and AC = 8
Next is the smaller triangle formed by connecting points D and E; triangle EAD, with EA = AD = 3 and the length of DE is unknown.
Because these triangles are similar, a simple ratio may be set up in order to calculate DE.
DE / AC = EA / AB
DE = 3/6 * 8
DE = 4 units
The domain would be x ≥ 0.
This is because the outlet cannot have profit before it was open. Therefore, the growth must be from year 0 to present. If they give a year as starting, you can have an upper limit too, but there is not enough information here to determine that information.
we will find number of non-zero elements on each rows
and then we add them
First row:
we can see that non-zero elements are
2 , 3.1 , 22 , 9
so, number of non-zero elements in first row =4
Second row:
we can see that non-zero elements are
21 , 3.2 , 6
so, number of non-zero elements in first row =3
Third row:
we can see that non-zero elements are
1 , 42 , 8
so, number of non-zero elements in first row =3
Fourth row:
we can see that non-zero elements are
40 ,4 , 6,14
so, number of non-zero elements in first row =4
Fifth row:
we can see that non-zero elements are
10 , 20 , 13 , 5 , 6.3
so, number of non-zero elements in first row =5
now, we can add them
so,
total number of non-zero elements = 4 +3+3+4+5
so,
total number of non-zero elements is 19...........Answer
