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natulia [17]
1 year ago
5

A heap of rubbish in the shape of a cube is being compacted into a smaller cube. Given that the volume decreases at a rate of 3

cubic meters per minute, find the rate of change of an edge, in meters per minute, of the cube when the volume is exactly 8 cubic meters.
Mathematics
1 answer:
inna [77]1 year ago
4 0

Answer:

-1/4 meter per minute

Step-by-step explanation:

Since, the volume of a cube,

V=r^3

Where, r is the edge of the cube,

Differentiating with respect to t ( time )

\frac{dV}{dt}=3r^2\frac{dr}{dt}

Given, \frac{dV}{dt}=-3\text{ cubic meters per minute}

Also, V = 8 ⇒ r = ∛8 = 2,

By substituting the values,

-3=3(2)^2 \frac{dr}{dt}

-3=12\frac{dr}{dt}

\implies \frac{dr}{dt}=-\frac{3}{12}=-\frac{1}{4}

Hence, the rate of change of an edge is -1/4 meter per minute.

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2 years ago
Please help!! I need to get this done! Im begging you, brainliest and points!
Viefleur [7K]

Answer:

<em>Solution; ( 1, 0 ), and ( - 3, 4 )</em>

Step-by-step explanation:

See procedure below;

First let us make these two functions ( y = -x + 1 , y = x^2 + x - 2 ) equivalent;

- x + 1  = x^2 + x - 2,

-x - x + 1 + 2 - x^2 = 0,

- 2x + 3 - x^2 = 0,

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Now factor the simplified equation;

x^2 + 2x - 3 = 0,

( x^2 - x ) + ( 3x - 3 ) = 0,

x ( x - 1 ) + 3 ( x - 1 ) = 0,

( x - 1 )( x + 3 ) = 0,

And solve for x;

x - 1 = 0, and x + 3 = 0,

x = 1, and x = - 3

Now substitute this value of x into the two functions as to receive the y  values for each x - value;

y = - ( 1 ) + 1, <em>y = 0 for x = 1</em>,

y = ( - 3 )^2 - 3 - 2, y = 9 - 3 - 2, <em>y = 4 for x = - 3</em>,

<em>Solution; ( 1, 0 ), and ( - 3, 4 )</em>

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