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kirza4 [7]
2 years ago
6

Express the null hypothesis and the alternative hypothesis in symbolic form. The owner of a football team claims that the averag

e attendance at games is over 68,800, and he is therefore justified in moving the team to a city with a larger stadium. H0: μ > 68,800 H1: μ ≤ 68,800 H0: μ = 68,800 H1: μ < 68,800 H0: μ < 68,800 H1: μ ≥ 68,800 H0: μ ≤ 68,800 H1: μ > 68,800
Mathematics
1 answer:
34kurt2 years ago
6 0

Answer:

H0: μ ≤ 68,800

H1: μ > 68,800

Step-by-step explanation:

The null hypothesis (H0) tries to show that no significant variation exists between variables or that a single variable is no different than its mean. While an alternative Hypothesis (H1) attempt to prove that a new theory is true rather than the old one. That a variable is significantly different from the mean.

For the case above;

The Null hypothesis is that the average attendance at games is less than or equal to 68,800.

H0: μ ≤ 68,800

The alternative hypothesis is that the average attendance at games is over 68,800.

H1: μ > 68,800

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2 years ago
Which of the following functions is graphed below?
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Answer:

The function graphed is y = Ix - 5I - 4 ⇒ answer D

Step-by-step explanation:

* Lets explain how to solve this problem

- From the graph

# The graph intersects the x-axis at x = 1 and x = 9

∴ The x-intercepts are 1 and 9

- We can find x-intercept by equate y by 0

* Lets equate the answers by zero to find the x-intercept

# y = Ix + 5I - 4

∵ Ix + 5I - 4 = 0

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∴ Ix + 5I = 4

- Remember in Ia + bI = c, then we have two answers :

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∴ x + 5 = 4 ⇒ subtract 5 from both sides

∴ x = -1

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∴ x + 5 = -4 ⇒ subtract 5 from both sides

∴ x = -9

∴ The x-intercepts are -1 and -9 not the same with figure

# y = Ix - 5I + 4

∵ Ix - 5I + 4 = 0

- Subtract 4 from both sides

∴ Ix - 5I = -4

- Remember in Ia + bI = c , c can't be negative because the absolute

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∴ We can't solve this equation

# y = Ix + 5I + 4

∵ Ix + 5I + 4 = 0

- Subtract 4 from both sides

∴ Ix + 5I = -4

- Remember in Ia + bI = c , c can't be negative because the absolute

 value is always positive

∴ We can't solve this equation

# y = Ix - 5I - 4

∵ Ix - 5I - 4 = 0

- Add 4 to both sides

∴ Ix - 5I = 4

- Remember in Ia + bI = c, then we have two answers :

 a + b = c  <em>OR </em> a + b = -c

∵ Ix - 5I = 4

∴ x - 5 = 4 ⇒ add 5 to both sides

∴ x = 9

- OR

∴ x - 5 = -4 ⇒ add 5 to both sides

∴ x = 1

∴ The x-intercepts are 1 and 9 the same with figure

* The function graphed is y = Ix - 5I - 4

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2 years ago
Bob is having a party and want to order some cake. there will be 57 guest and he wants to make sure that everyone gets a slice o
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A random draw is being designed for 210 participants. A single winner is to be chosen, and all the participants must have an equ
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2 years ago
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