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1 year ago

A 4-ounce cup of coffee costs $8.00. How much would a 3-ounce cup of cofee codt?

2 answers:

5 0

To solve this, we must first find out the cost-per-ounce of a cup of coffee. Assuming that the rates are flat, then we can just divide the 8-dollar-cost by the 4-ounce cup that it buys.

8 / 4 = 2

The cost-per-ounce of a cup of coffee is $2.
Now, we just have to multiply the cost-per-ounce by the amount of coffee we want to find out the cost of.

2 * 3 = 6

With all else constant, a 3-ounce cup of coffee would cost $6.
Hope that helped! =)

CaHeK987 [17]1 year ago

4 0

Set this up as a proportion. 4/8=3/? Call your unknown number x and solve by cross multiplication. x=6

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The total number of degrees, D, in an n-sided polygon is given by the formula D=180(n-2). When Janelle solves for n, she gets n=

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<span>D = 180 * (n -2)
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So, the answer is "A"
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n = (D / 180) +2
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Source:
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2 years ago

Suppose f and g are continuous functions such that g(2) = 6 and lim x → 2 [3f(x) + f(x)g(x)] = 36. find f(2).

True [87]

Answer: f(2) = 4

Step-by-step explanation:

F(x) and g(x) are said to be continuous functions

Lim x=2 [3f(x) + f(x)g(x)] = 36

g(x) = 2

Limit x=2

[3f(2) + f(2)g(2)] = 36

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1 year ago

Which of these conditions might be true if polygons ABCD and KLMN are similar? The measures of corresponding angles of ABCD and

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Answer: The correct option is

(A) The measures of corresponding angles of ABCD and KLMN are equal, but the lengths of corresponding sides of ABCD are half those of KLMN.

Step-by-step explanation: We are given to select the correct condition that might be true if polygons ABCD and KLMN are similar.

Two polygons are said to be SIMILAR if corresponding angles are congruent and corresponding sides are proportional.

So, options (B), (C), (D) and (E) are not correct because they contradict conditions of similarity.

In option (A), we have

The measures of corresponding angles of ABCD and KLMN are equal. So, they must be congruent.

And the lengths of corresponding sides of ABCD are half those of KLMN.

So, we can write

$AB=\dfrac{1}{2}KL,~~BC=\dfrac{1}{2}LM,~~CD=\dfrac{1}{2}MN,~~AD=\dfrac{1}{2}KN\\\\\\\Rightarrow \dfrac{AB}{KL}=\dfrac{BC}{LM}=\dfrac{CD}{MN}=\dfrac{AD}{KN}=\dfrac{1}{2}.$

Therefore, the corresponding sides are proportional.

Thus, option (A) is true if two polygons are similar.

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