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2 years ago

10q - 30 is equivalent to _____. 3(q - 10) 10(q - 30) 10(q - 3)

Mathematics

2 answers:

shutvik [7]2 years ago

8 0

10q - 30 = 10 · q - 10 · 3 = 10(q - 3)

liubo4ka [24]2 years ago

5 0

Answer:

$10(q-3)$

Last option is correct.

Step-by-step explanation:

We have been given the expression $10q-30$

The greatest common factor or GCF of the given expression is 10.

Hence, we factored out 10. When we factored out 10, we have to divide all the terms by 10.

$10(\frac{10q}{10}-\frac{30}{10})$

On simplifying, we get

$10(q-3)$

Therefore, the expression $10q-30$ is equivalent to $10(q-3)$

Last option is correct.

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Licemer1 [7]

Answer and explanation:

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2 years ago

Do you think a sequence of translations across the x- or y- axis and/or reflections on a figure could result in the same image a

vlabodo [156]

I think just two reflections would do it.

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5 0

2 years ago

Read 2 more answers

R+5/mn=p solve for m

AnnZ [28]

Answer:

$\bold{m\ =\ \dfrac5{(p-r)n}}$

Step-by-step explanation:

$\bold{r+\dfrac5{mn}\ =\ p}\\\\ {}\quad-r\qquad-r\\\\{}\ \ \bold{\dfrac5{mn}\ =\ p-r}\\\\{}\ ^{_\times}(mn)\quad ^{_\times}(mn)\\\\{}\quad\bold{5\ =\ (p-r)^{_\times}(mn)}\\\\\div(p-r)\quad\div(p-r)\\\\{}\ \ \bold{\dfrac5{p-r}\ =\ mn}\\\\{}\quad \ \div n\quad\ \ \div n\\\\\bold{\dfrac5{(p-r)n}\ =\ m}$

If you mean (r+5)/mn then:

$\bold{\dfrac{r+5}{mn}\ =\ p}\\\\{}\ ^{_\times}(mn)\quad ^{_\times}(mn)\\\\{}\ \bold{r+5\ =\ pmn}\\\\\div(pn)\quad\div(pn)\\\\{}\ \ \bold{\dfrac{r+5}{pn}\ =\ m}$