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Zigmanuir [339]
2 years ago
8

1. Kellie and her sister Ashley are training for a marathon. Kellie ran 10 mi in 75 min. Ashley ran 15 mi in 120 min. Which stat

ements are true? If a statement is not true, explain why. Show your work.
(a) Kellie’s minutes-per-mile pace was faster than Ashley’s minutes-per-mile pace.
(b) Kellie ran 8 mph.
(c) Ashley ran 12 mi in 90 min.
Mathematics
2 answers:
skad [1K]2 years ago
8 0

(a) Kellie’s minutes-per-mile pace was faster than Ashley’s minutes-per-mile pace.

True

10/75 = 0.14

15/120 = 0.13

(b) Kellie ran 8 mph.

True

10 ÷ 1.15 = 8

(c) Ashley ran 12 mi in 90 min.

False

Speed = 7.5 mph

7.5 × 1.5 = 11.25 mi

Elden [556K]2 years ago
4 0

Answer:

Step-by-step explanation:

Kellie ran 10 miles in 75 minutes. This means that Kellie's speed is

10/75 = 0.1333 miles per minute.

Ashley ran 15 miles in 120 minutes. This means that Ashley's speed is

15/120 = 0.125 miles per minute.

Considering the given statements,

a) Kellie’s minutes-per-mile is

75/10 = 7.5 minutes per mile

Ashley’s minutes-per-mile pace is

120/15 = 8 minutes-per-mile

Therefore, it is true that Kellie’s minutes-per-mile pace was faster than Ashley’s minutes-per-mile pace.

b)75 minutes = 1.25 hours

Kellie's speed per hour is

10/1.25 = 8 mph

It is true

c ) Ashley's speed is

15/120 = 0.125 miles per minute. In 90 minutes, she will run

90 × 0.125 = 11.25 miles

So it is false

Ashely ran 11.25miles in 90 min.

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True or False? A circle could be circumscribed about the quadrilateral below.
SVEN [57.7K]

Answer:

<em>The correct answer is:   False</em>

Step-by-step explanation:

<u>If the sum of the opposite angles in a quadrilateral is 180°</u>, then a circle can be circumscribed about the quadrilateral.

Here,  \angle B+\angle D= 110\°+90\° = 180\°

but,  \angle A+\angle C= 70\°+90\°= 160\°

So, a circle can't be circumscribed about the given quadrilateral.

7 0
2 years ago
Read 2 more answers
The distance between place A and place B is 60 miles. the distance from place A to place C is 15% of the distance from place A t
iren [92.7K]

\frac{15}{100}  =  \frac{d}{60}  \\  100d = 900 \\ d = 9

8 0
2 years ago
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If f (x) = StartFraction x minus 3 Over x EndFraction and g(x) = 5x – 4, what is the domain of (f circle g) (x)?
alexandr1967 [171]

Answer:

<h2>The domain is all real values of x except \frac{4}{5}.</h2>

Step-by-step explanation:

The function, f(x) = \frac{x - 3}{x}.

g(x) = 5x - 4.

Hence, (f circle g) (x) = \frac{5x - 4 - 3}{5x - 4}.

We need to find the domain of (f circle g) (x) .

The domain means the set of values of x, for which we will get a real value of (f circle g) (x).

The function will not give a real value when, 5x - 4 = 0 that is x = \frac{4}{5}.

Hence, the domain of the function will be all real values of x rather than \frac{4}{5}.

5 0
2 years ago
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Which sequence of transformations produces R'S'T' from RST? On a coordinate plane, triangle R S T has points (0, 0), (negative 2
arsen [322]

Answer:

Step-by-step explanation:

Given is a triangle RST and another triangle R'S'T' tranformed from RST

Vertices of RST are (0, 0), (negative 2, 3), (negative 3, 1).

Vertices of R'S'T' are  (2, 0), (0, negative 3), (negative 1, negative 1).

Comparing the corresponding vertices we find that x coordinate increased by 2 while y coordinate got the different sign.

This indicates that there is both reflection and transformation horizontally to the right by 2 units

So first shifted right by 2 units so that vertices became

(2,0) (0,3) (-1,1)

Now reflected on the line y=0 i.e. x axis

New vertices are

(2,0) (0,-3) (-1,-1)

8 0
2 years ago
Juana compró una camioneta 4x4 a S/ 42 000; además, sabe que la camioneta se depreciará (bajará su precio) en forma lineal duran
prohojiy [21]

Answer:

Una relación lineal es de la forma:

y = a*x + b.

donde a es la pendiente y b es la ordenada al origen.

en este caso, y es el precio de la camioneta, x es el numero de años que pasaron, a es la razon de depreciación de la camioneta y b es el precio inicial de la camioneta, b = $42,000.

Sabemos que después de 5 años, el precio de la camioneta es 21,000, entonces podemos resolver:

$21,000 = a*5 + $42,000

a*5 = $21,000 - $42,000 = -$21,000

a = -$21,000/5 = -$4,200

Esto significa que el precio decae $4,200 por año

4 0
2 years ago
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