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kari74 [83]
2 years ago
11

True or False? A circle could be circumscribed about the quadrilateral below.

Mathematics
2 answers:
SVEN [57.7K]2 years ago
7 0

Answer:

<em>The correct answer is:   False</em>

Step-by-step explanation:

<u>If the sum of the opposite angles in a quadrilateral is 180°</u>, then a circle can be circumscribed about the quadrilateral.

Here,  \angle B+\angle D= 110\°+90\° = 180\°

but,  \angle A+\angle C= 70\°+90\°= 160\°

So, a circle can't be circumscribed about the given quadrilateral.

Sonbull [250]2 years ago
4 0

Answer:

the answer was false

Step-by-step explanation:

apex said so

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Consider the following formula used to estimate height, h, of a seedling after w weeks since planting:
svp [43]

Answer:

Option B. w=5h-8

Step-by-step explanation:

we have

h=(\frac{1}{5})w+(\frac{8}{5})

Solve for w

That means ----> isolate the variable w

Multiply by 5 both sides to remove the fraction

5h=w+8

subtract 8 both sides

5h-8=w+8-8

5h-8=w

Rewrite

w=5h-8

4 0
2 years ago
Show that the three points whose position vectors are 7j+ 10k,-i + 6j+6k and - 4i + +9j + 6k form an isosceles right
Novay_Z [31]

Answer:

AB = √18 , BC=√18 and CA =4

AB²+BC²  = CA² and AB=BC

ΔABC isosceles right  angled triangle.

Step-by-step explanation:

Given vectors are  7j+ 10k,-i + 6j+6k and - 4i + +9j + 6k

A( 0,7,10), B( -1,6,6) C(-4,9,6)

AB⁻ = OB-OA = -I+6j+6k-(7j+10k) = -I-j-4k

AB = \sqrt{1+1+16} = \sqrt{18}

BC = OC-OB = -4i+9j+6k-(-I+6j+6k) = -3i+3j

BC=\sqrt{9+9} =\sqrt{18}

CA = OA-OC = 7j+10k - (- 4i + +9j + 6k ) = 4i-2j+4k

CA = \sqrt{16+4+16} =\sqrt{36} =4

Since AB²+BC²  = CA²

And AB=BC

Therefore it follows that ΔABC is a right angled isosceles triangle



3 0
2 years ago
Question and answer choices are in the screenshot. THANK YOU!!
Anika [276]
I 11 x - 22 I > 22
∴ 11x-22 > 22          OR          (11x -22) < -22
∴ 11 x > 44             ::::::::          11x - 22 < -22
    x > 4                   ::::::::              x < 0

∴ x ∈ ( -∞ , 0 ) ∪ ( 4 , ∞)
∴ The correct choice is number 1
The solution is attached in the figure

5 0
2 years ago
Nathan is out rafting. He rafts 16 miles with the river current. At the end of 16 miles, he turns around and rafts the same dist
Novosadov [1.4K]
S = d/t

st = d

t = d/s

The time going is t1.
The time returning is t2.
The total time is 4 hours, so we have t1 + t2 = 4

The speed of the current is c.
The speed going is 9 + c.
The speed returning is 9 - c.

t1 = 16/(9 + c)

t2 = 16/(9 - c)

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4 = 16/(9 - c) + 16/(9 + c)

1 = 4/(9 - c) + 4/(9 + c)

(9 + c)(9 - c) = 4(9 - c) + 4(9 + c)

81 - c^2 = 36 - 4c + 36 + 4c

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c^2 - 9 = 0

(c + 3)(c - 3) = 0

c + 3 = 0   or   c - 3 = 0

c = -3   or   c = 3

We discard the negative answer, and we get c = 3.

The speed of the current is 3 mph.
7 0
2 years ago
Read 2 more answers
Kiley and her parents traveled to visit her grandmother. They drove 24.3 miles from their house to the airport in hour. At the a
Tju [1.3M]
The answer is  just 24.3 miles.

The questions asked "How long was the ride from Kiley's house to the airport?"

The first sentence of the problem reads "They drove 24.3 miles from their house to the airport in an hour". The rest of the information isn't necessary to find this answer.
6 0
2 years ago
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