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gladu [14]
2 years ago
10

Jada earned $50 babysitting and plans to use the money to go to the fair l.admission to the fair is $5 and each ride is $2.50.wh

ile at the fair she buys a funnel cake for $3.what is the maximum number of rides jada can ride?
​
Mathematics
2 answers:
Zielflug [23.3K]2 years ago
3 0

Answer:

16

Step-by-step explanation:

5+3+2.50x=50

8+2.50x=50

-8 on both sides

2.50x=42

divide both sides by 2.50

x=16.8

She can ride 16 rides.

Annette [7]2 years ago
3 0

Answer:

The maximum number of rides is 16

Step-by-step explanation:

She has a total of $50 and spends $3 for the cake and $5 for admission. She has to spend $2.50 for every ride.

Your equation would be set up as:

$50=$5+$3+$2.50x

You would combine like terms and get

$50=$8+$2.50x

Subtract the $8 from $50 and you get

$42=$2.50x

Divide each number by 2.50 and you get

16.8=x, you cannot have a decimal as an answer since she cannot ride eight tenths of a ride so the maximum number of rides is 16

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<em><u>The intervals included in solution are:</u></em>

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