Answer:
(D)The midpoint of both diagonals is (4 and one-half, 5 and one-half), the slope of RP is 7, and the slope of SQ is Negative one-sevenths.
Step-by-step explanation:
- Point P is at (4, 2),
- Point Q is at (8, 5),
- Point R is at (5, 9), and
- Point S is at (1, 6)
Midpoint of SQ 
Midpoint of PR 
Now, we have established that the midpoints (point of bisection) are at the same point.
Two lines are perpendicular if the slope of one is the negative reciprocal of the other.
In option D
- Slope of SQ

Therefore, lines RP and SQ are perpendicular.
Option D is the correct option.
Answer:
the lines arent parallel, so you cant use corresponding angles theorem
We can use t=x^2 to solve this
Once we do that we will have simple square equation which we know how to solve.
t^2 + 3t + 2 = 0
t1 = -1
t2 = -2
x1 = √-1 = i
x2 = -i
x3 = √-2 = i√2
x4 = -i√2
Make sure you know that i^2 = -1 and (-i)^2 = -1 which gives us solutions we got...