The shifts of the sinus function can be described with the formula:
<span>a<span>sin<span>(<span><span>bx</span><span>−c</span></span>)</span></span></span>+<span>d, where
a is the amplitude
b is the period
c is the phase shift
d is the vertical shift
So, the graph y=3sinx is phase shifted. The phase shift can be calculated as c/b= pi/3/1=pi/3
So, the function is phase shifted for pi/3.</span>
Answer:
The radius of the circle is 5 units
Step-by-step explanation:
Given in the question,
centered point = (-3 , 2)
a point in the circle = (1,5)
To find the radius of circle we will use the circle equation
(x – h)² + (y – k)² = r²,
with the centre being at the point (h, k) and the radius being r.
Plug values in the equation
(1 – (-3))² + (5 – 2)² = r²
(1+3)² + (3)² = r²
4² + 3² = r²
25 = r²
r = √25
r = 5
Answer:
The anwers is D
Step-by-step explanation:
I see the solution in three steps.
1.) RS ⊥ ST, RS ⊥ SQ, ∠STR ≅ ∠SQR | Given
2.) RS<span>≅RS | Reflexive Property
3.) </span><span>△RST ≅ △RSQ | AAS Triangle Congruence Property</span>
