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Alla [95]
1 year ago
5

Unit 3: Parallel & Perpendicular Lines Homework 5: Linear Equations Slope-Intercept & Standard Form

Mathematics
1 answer:
Alona [7]1 year ago
4 0
And you can see that I don’t have respect you don’t deserve that you
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Step-by-step explanation:

ESLAC  

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Evaluate e − 1 2 f e− 2 1 ​ fe, minus, start fraction, 1, divided by, 2, end fraction, f when e = 15 e=15e, equals, 15 and f = 2
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The answer 456 fe
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Given that line s is perpendicular to line t, which statements must be true of the two lines? Check all that apply.
artcher [175]
The basis to respond this question are:

1) Perpedicular lines form a 90° angle between them.

2) The product of the slopes of two any perpendicular lines is - 1.

So, from that basic knowledge you can analyze each option:

<span>a.Lines s and t have slopes that are opposite reciprocals.

TRUE. Tha comes the number 2 basic condition for the perpendicular lines.

slope_1 * slope_2 = - 1 => slope_1 = - 1 / slope_2, which is what opposite reciprocals means.

b.Lines s and t have the same slope.

FALSE. We have already stated the the slopes are opposite reciprocals.

c.The product of the slopes of s and t is equal to -1

TRUE: that is one of the basic statements that you need to know and handle.

d.The lines have the same steepness.

FALSE: the slope is a measure of steepness, so they have different steepness.

e.The lines have different y intercepts.

FALSE: the y intercepts may be equal or different. For example y = x + 2 and y = -x + 2 are perpendicular and both have the same y intercept, 2.

f.The lines never intersect.

FALSE: perpendicular lines always intersept (in a 90° angle).

g.The intersection of s and t forms right angle.

TRUE: right angle = 90°.

h.If the slope of s is 6, the slope of t is -6

FALSE. - 6 is not the opposite reciprocal of 6. The opposite reciprocal of 6 is - 1/6.

So, the right choices are a, c and g.
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1 year ago
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Jeremy drew a polygon with four right angles and four sides with the same length. Name all the polygons that he could have drawn
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Square. 

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A rectangle is a parallelogram, so parallelogram.

Equilateral.

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1 year ago
The statement tan theta -12/5, csc theta -13/5, and the terminal point determined by theta is in quadrant 2."​
Harlamova29_29 [7]

Answer:

Answer C:

Cannot be true because csc(\theta)  is greater than zero in quadrant 2.

Step-by-step explanation:

When the csc of an angle is negative, since the cosecant function is defined as:

csc(\theta)=\frac{1}{sin(\theta)}

that means that the sin of the angle must be negative, and such cannot happen in the second quadrant. The sine function is positive in the first and second quadrant.

Therefore, the correct answer is:

Cannot be true because  csc(\theta)  is greater than zero in quadrant 2.

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