Answer:
Step-by-step explanation:
a)
- p = Total Number of Defects / Sample Size x Number of Samples
- z = Number of standard deviation = 3
- σ = Standard deviation of sampling distribution
- σ = p (1- p) / n = 0.0336 (1- 0.0336) / 300 = 0.0336 x 0.9664 / 300 = 0.0104
- Here, n = number of observations in each sample
- UCL = p+zσ = 0.0336 + 3(0.0104) = 0.0336 + 0.0312 = 0.0648 = 0.065
- LCL = p-zσ = 0.0336 - 0.0312 = 0.0024 = 0.002
b) Hence, Lower control limit cannot be a negative number as percent defective cannot be a negative number. As such, No. Percent of defective records cannot be a negative number.
Amount of walnuts=
Amount of almonds=
Amount of pecans=
Total amount=
LCM is 4 so sum is =
=
As given, Carmela divides the mixed nuts into 3/10 kilogram bags so number of bags will be:

=
= 5
Hence, answer is 5 bags.
Answer:
Step-by-step explanation:
hello :
100+(n-2)² = 149
100-100+(n-2)² = 149-100
(n-2)² = 49
(n-2)² - 49 =0 but 49=7²
(n-2)² - 7² =0 use identity : a²-b²=(a-b)(a+b)
(n-2-7)(n-2+7)=0
(n-9)(n+5)=0
n-9=0 or n+5=0
n=9 or n=-5
Answer:
See Bottom!
Step-by-step explanation:
This may seem bad, but the answer should be 2191919/1000000
If you require more assistance, please let me know at the bottom.
To find the area of his exclusion zone you would need to understand that a triangle with dimensions of 3, 4, and 5 represent a right triangle.
This means the exclusion zone would be applied to the base and the height of the triangular space.
You would add 2 km to the 3 km, and 2 km to the 4 km to create a new height of 5 km and a new base of 6 km.
Please see the attached picture to understand this.
You will find the area of the total space created by the new triangle and subtract the space represented by the original triangle to find the area of the exclusion zone.
(1/2 x 6 x 5) - (1/2 x 4 x 3)
15 km² -6 km² equals 9 km².
The exclusion space is 9 km².